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#3 Re: Help Me ! » bernouli » 2011-05-01 22:53:58

i was told 2 use the riemann zeta function. got stuck. can u manage?

#4 Help Me ! » bernouli » 2011-05-01 22:28:26

Kryptex_android
Replies: 10

need help with this guys.

Prove for all integers m ≥ 3, there is a bound |B(m)| < 3.289868... x m!/{(2*pi)^m}, where B(m) denotes the mth-Bernoulli number.

#5 Help Me ! » equivalence relations using functions » 2011-04-17 14:59:43

Kryptex_android
Replies: 1

Help me out with the question. I managed to do it myself somewhat, but would like a second opinion.

Let S be the set consisting of functions f : [0; 1] ! R such that
(i) f is continuous, and
(ii) f(x) > 0 for all x 2 [0; 1].
Show that the relation R on S defined by
fRg if and only if
∫1 and 0
f(x):dx ·
∫1 and 0
g(x):dx
is not a partial ordering on S.
Which out of reflexivity, antisymmetry, transitivity fails, and why?

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