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#1 Re: Help Me ! » Interesting question MIND FREAKING » 2011-06-12 01:32:41
I Am Having Doubts I A Bunch Of Questions Would You All Solve Them For Me Please
#2 Re: Help Me ! » Interesting question MIND FREAKING » 2011-06-12 01:30:57
No need to worry my friends
i got the question from one of my books
at back the answer was {2}^{1/2}
I THINK THE QUESTION IS WRONG I THINK IT SHOULD BE
#3 Re: Help Me ! » Interesting question MIND FREAKING » 2011-06-10 20:26:32
We can also have:
All are wrong ANSWERs
answer is B) {2}^{1/2}
#4 Re: Help Me ! » Interesting question MIND FREAKING » 2011-06-10 20:25:20
hi
I agree with gAr's analysis. But do A, B and C exist (in real numbers let's say) ?
so
so I plotted the graph of y = logx and the graph of y = x.logk, using 'x' to replace 'A' and trying various values for logk
see graph below.
Either the line fails to hit the curve at all; or it touches as a tangent once; or it crosses twice (which I show with logk = 0.11)
But we also want B and C to have this property so I think this means that if k, A, B and C exist in reals then either
(i) A = B = C
or
(ii) at least a pair are equal, let's say wnlog, B = C
That's it for the moment I'm afraid.
Bob
All are wrong ANSWERs
answer is B) {2}^{1/2}
#5 Re: Help Me ! » Interesting question MIND FREAKING » 2011-06-10 03:43:39
dear gAr,
you have taken k as A^1/A ,B^1/B, C^1/C
then how can you write it as k^ABC+ k^ABC+ k^ABC ???
please explain
#6 Re: Help Me ! » Interesting question MIND FREAKING » 2011-06-09 16:41:05
Hi,
I'm getting:
what is the method used
#7 Re: Help Me ! » Interesting question MIND FREAKING » 2011-06-09 16:40:04
also the method
#8 Help Me ! » Interesting question MIND FREAKING » 2011-06-09 05:22:26
- devkumararora
- Replies: 24
Whick of the following is equal
?A)
B)
C)
C)
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