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#1 Re: Puzzles and Games » integ » 2008-08-02 11:04:37

I'd say this is a basic integration question checking the basics

Refer to any book on definite integration, you'll find a property that definite integration of any f(x) from 0 to a equals integration of f(a-x) from 0 to a

So first write I as the required integral and then use the above property to rewrite I

Then add both the equstions and you'll see that 2I=x]0 to pi/2    becos f(x) + f(a-x)=1 here ( this is a whole class of questions)

so answer is pi/4

WHy you couldnt do it may be cos you are accustommed more to using indefinite and coulsnt get into the definite system which is simpification first

Cheers

#2 Re: Help Me ! » Complex Number question » 2008-08-02 10:52:32

well obviously it will happen when you calculate locus
Cos locus is basically a algebraic equation which is inteprated in geometric terms by you
So you need to figure it out on the Argand Plane which arc you want
The minor arc is the answer I think so it is to be asked in a question objectively about the major arc otherwise you need not mention anything if it's just an equation or if you're so very much into describing it. write it as the minor arc of the circle( described above) passing through the given points

Draw the diagram (which's simple here) you can easily make a rule to decide between major and minor arcs in such a locus problem

Cheers

#3 Introductions » Hi Everyone » 2008-08-02 10:42:04

Rohan.A
Replies: 5

Hi Guys
I am Rohan from New Delhi
I am doing my integrated Mtech in Mathematics and Computing from iit delhi
Its good to see people discussing mathematics
I hope not only to make my mathematics good but make some good friends as well
Anyone having any query regarding anything related to iit delhi can email me at my address and rest I'll try my best to participate in the forums on the web siteroflol

#4 Re: Introductions » Hello I am Abhishek » 2008-08-02 10:38:14

Hey Abhi
WElcome here
I am In IIT Delhi
Studying mathematics and Computing integ.. Mtech
joined it just recently

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