Math Is Fun Forum

(Just so you know, I am acknowledging this website in my log for all the help you guys have been giving me. My teacher said I can get all the help I need as long as I acknowledge it.)

Thanks a million.

So then l-x=l-[4l/(pi+4)]
= L*Pi/(pi+4)

Is that the answer? That's the minimum right? How do I find the max? I imagine it is just using the whole length of rope for a circle, but how to I prove that? I can prove that a circle and a square of a set perimeter, the circle will have the biggest area.

Hey bobbym. Please see post above. How do I solve it equated to 0?

thanks. I obviously need to add x^2/16 to the end result you have there (I am guessing) and so do I do the cross multiplying?

Also, how do you so all that maths set up on the forum?

Okay, what's the correct way to square it.

How do I do that. Do I first need to get rid of the brackets? So it would be

x^2/16+Pi((L^2-x^2)/2pi^2)
?

Then where do I go? Can we take it a step at a time please?

It's working today

Anon, I have not yet. How would I do that?
Bob, I am guessing it's still answer in process. I get so far and then couldn't get further. I think the sec^3 theta tan theta is a hint.

Okay. so the first thing I need to do is find A and B as shown above?

Then, how do I integrate the fraction. My teacher said it was something to do with Partial Fractions, and did say if i couldn't do the question not to worry because I've not studied partial fractions before, but I would like to at least understand how the answer is derived.

anonimnystefy, that is classic. I love it