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Also, the method in this lesson is for finding intercepts. So, yes, to find the intercepts you always start by letting x=0.
(In particular letting x=0 lets you find the y-intercept.)
2x+3y=6
x=0: 2(0)+3y=6
0+3y=6
3y=6
Not sure if I'm answering your question...?
The substitution u=lnx will do the trick! Then du=(1/x)dx and your integral reduces to u^2 du.
I wish there was some way to use actual math symbols. I see everyone else using them but I don't see the option here.
How many conjugates of (123)(456) are there in S6? This is probably pretty basic, but this counting stuff always messes with me!
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