You are not logged in.
Hi all,
Given a linear system
, and , we know that:.What nonzero vectors of b and
, assuming that , will equality hold?but what is the steps taken to solve it?
do i need (xy^2)(x+y)=6 or something?
What is the slope of the tangent to the curve y^3x + y^2x^2 = 6 at (2,1)
I'm confused what to do am I supposed to isolate y??
thanks a lot
oh i see i messed up calculations. How exactly can you find b though?
I tried AM-GM with
and but that had netted no real progress. I'm confused in how x+y=1 comes in to be handythanks for the clarifications.
I'm confused on how you found the answer to a.
g(2015) is close to g(2016)=g(672)=g(224). g(224) is close to g(225)=g(3)=g(1). So g(2015) maximum seems to be g(1)+2. So is the answer not 3?
I am a little confused on this notation and what it means? more specifically what does it mean N->N
and also what does it mean on the line with: g(n+1)-g(n)
Why did you guys remove {x}
How do u solve this?
Oh I get it, I'll post when I am not on mobile
11. Write as the sum or difference of logarithms:
I got (a+2e-3)^2=(a+3e+2)(a+e-4) which gives 10a+e^2+22e-4=0
Derp I thought that 3^0+1 was 1 my bad
I tried S=the thing posted and S/3, not exactly sure how to do it, I have 3^k/(3^k+1)
with r = common ratio.
So eliminate b, c and d from the GP equations and then divide the first by the second and first by the third to eliminate r and leave a pair containing just a and e.
How exactly do you "eliminate b"
Using the above, how would you get 2?
Sounds intuitive, can you try to explain what your thought process was?
o.O how in the world do you get that...
I used the method before I posted but didn't get anywhere
Find the arithmetic sequence a, b, c, d if a−2, b−4, c−3, d+2 is a geometric sequence.
I have no clue either.