Math Is Fun Forum

sorry to bug in, but here is were the logic you have fails, and the book is right
instead of having a-d and a+d, make the a-d=m and a+d=n
what you got:
d/m+a/n=(dn-am)/mn
ok, plug in the stuff
(d(a-d)-a(a+d))/((a+d)(a-d))
big excalmation point, sighn warnings
now if you split them the top part
da-dd-aa-ad=-dd-aa
bottom
(aa+ad-ad+dd)=aa-dd
simplification is only posible is some cases!!!
the a is a variable(wich i am assuming) so is b
if you go with a =7 and d = 1
thy them out
what do you have
7/(1+7)-1/(1-7)=7/8+1/6=25/24

to the formula you have got you get a minus(aa+dd) wich is allways negative or 0 and the solution is positive

you are absolutely right,
i got nothing but a bunch of sin and x^4th power, and i do beleve what i am doing is wrong,
but still , i will try and solv this integral, who knows maby i will get lucky and do it , and i hope it is equal to something interesting
new stuff to learn
later edit:
ow god please do not tell me it is equal to pi/2

my apologies for bad English, basically you are asking me if i kno how much is lim when x tends to infinity of 3x^3/(x^3+etc), just some simple math 3/1=3(no problem we got this
1^ infinit power=(we got this ) a function tends to 0 we get 1+that function to the power of 1 over that functon[wich is e] and that function again to the power, and if any other power remains(usually dose) you just to the reamining limit
(if someone is reading this and i just spoiled your joy of finding a solution to some problem,sorry)
do not ask me , maby he felt sadistic or thought we cannot do it
we found the easy way to solve for m in the following eq( a*sin(x)+b*cos(x)=m[probem was so find the min and max values for m given a and b(our pik, and the easy solution my colleague found is to just use tg(x/2)=t and the rest is math)]) so we are not that uncooperative, but if we have no idea were to look, anyway, thanq for at least trying to give me some direction on the solution will keep update if found solution solo or whatnot,

later edit, hold the phone, that pdf looks promising, leme just read it, may take a while

they are problems for the summer vacation, for us the nerds, omg, me a nerd, now i have done it, anyways it is just 3 pieces of paper with problems on them, but since i have no idea on how to solve these specific problems, and neither do my colleagues kno were to start at least, I had the idea to ask, found easy ways to solve some of the problems in this sheets, but for these ones, not as much as a hint, (re-looking Euler Mclaurin summation atm,) stil not convinced that this is the way, but since you got some results, might just be worth checking, also finding and just typing results on the paper is of no use, if we get this on a test next year, who will explain this again, we need to understand what we are doing if we are to help others so we get passing grades, and you got 0 and 1 sses, all we got were quote"say infinity, n tends to infinity so infinity", sorry for long post and boring math trolling, but seriously what or how did you get those answers,
later edit:you have a talent or someone showed this type of problems before and now you are just teaching it, anyways, many thx for the reply, congratulations on finding anything different from infinite and if you  have the patience please share the method you used

it just means that there are 7 problems and that they are all exacly the same exept for the k* part
a is just k
b is k^2
c is sqrt(k)
d is sqrt(k^2+1)
e is sqrt(k^2-1)
f is (k+1)(k+2)..(k+n)
g is (k)!*n!

so if you would ask what c is at the example :
lim when n tends to infinity of (sum from k=1 to n for(1/(n+sqrt(k))