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Oh, OK thanks
I mean I shouldn't do that in this problem
But i can't still solve for n
Any way to do it?
Thanks, its correct. Can you please tell me how you found this? Please
Oh i got it thanks!
yeah! , thanks.
Can you say how you found it?
a is base
well, just the type matters, i mean we have infinit amount for each color.
yes 300 different colors.
original question is:
there can be 300 types of neuron in a nerve, how many neuron should be in a nerve so we be sure more than 50% that we have two neuron with same type in that nerve?
imagine we have 300 different balls possible, at least how many balls should we have so we be sure more than 50% that we have two balls with same color?
i guess the equation would be this (not sure):
300 * C(n,2) * (1/300)^2 * (299/300)^(n-2) ≥ 0.5
and i got answer 19
can anyone solve it?
Well there is no magic, its so simple:
as you see
1²-0²=1
2²-1²=3
3²-2²=5
.
.
.
x²-(x-1)²=odd number because:
x²-(x-1)²=x²-(x²-2x+1)=x²-x²+2x-1=2x-1
2k-1 always gives odd numbers
we have two functions:
f(x)=log(a,x)
g(x)=a^x
a=??
in what "a" the graph of these two hit each other in only one point?
i think it has the same meaning as:
in what "a" the following equation has only one answer:
log(a,x)=a^x
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