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Oh I see where my error was, left my calculator in degrees and forgot to change it over to radians!
Thank you so much for your time and effort, I greatly appreciate it
Final = 3.7sin(1.7 *1.1) = 0.1207378929
Initial = 3.7sin(1.7 * 1) = 0.1097651031
Final - Initial = 0.1207378929 - 0.1097651031 = 0.0109727898
Change in time = 1.1-1 = 0.1
Change in distance/change in time = 0.0109727898/ 0.1 = 0.109727898, to 4 decimal places -> 0.1097
I'm not sure still where my error is :s
I started an online assignment that appeared to be simple, and imputed numbers into the formula that gave me the correct answer otherwise, however when I did the exact same work for this question the answer I got is wrong. I've tried it over and over, asked for help, and somehow no one seems to be able to give me an answer thus far, and I don't have the correct answer to compare my work to. Can you please point out my error, and a way to correct it in order to obtain the proper answer? Thank you in advance
Question;
At a time of t seconds, a particle moves a distance of s meters from its starting point, where s=3.7sin(1.7t).
Find the average velocity (correct to four decimal places) between t=1 and t=1+h for the following values of h.
If h=0.1 then the average velocity over the time period [111] equals
Answer;
V= Change in distance/Change in time
V=(3.7sin(1.7 * 1.1)-3.7sin(1.7 * 1))/(1.1-1)
V= 1.0449 m/s
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