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okay, thank you. I'm submitting the lesson hopefully I get 20/20 !
so if I simplify, it would be 112.82 m^2?
I guess the grey area is the shaded region.
it looks tough because you have to figure out the shaded region.
okay, thank you!
now question 20 is hard, I never understand and remember how to do it
20. Calculate the area of the shaded region in the figure shown.
5.04 ft?
the height is 5.04?
cos(65) = x/12
.42=x/12
5.04=x
well that's what my teacher put in the question, so I didn't write the whole number.
so:
cos(65) = x/12
.42=x/12?
cos(65)=0.42
oh okay. no I don't know hot to get cos(65)
I did 65 * 12.
cos(65 degrees) = x/12
cos(780)=x
a little. we did one lesson on it.
sin = opp./hyp.
cos = adj./hyp.
tan = opp./adj.
What do you mean? I don't understand what formula I would be using to get the answer.
18. In the diagram shown, a 12-foot slide is attached to a swing set. The slide makes a 65 degree angle with the swing set. What is the height of the top of the slide (as close as you can get)?
sin 65 degree = 0.91
cos 65 degree = o.42
tan 65 degree = 2.14
What is the length of the line segment with endpoints (-8,6) and (-10,-1)?
Okay, thank you, enjoy your day.
yes, sorry I didn't notice that.
for 15 I'm not sure what formula I should use.
120 right?
how did you get 60?
okay, so my answer for 14 is wrong?
Yes the hexagon in the middle.
would 13 be:
(n-2)180
(6-2)180
(4)180
720
would 14 be:
720/6
120
Okay, I understand.