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Wow! Oh my gosh thank you thank you thank you thank you so much!!! You guys did more than I expected, thank you guys!
Hi,
Prove that
sqrt((2x^2 - 2x + 1) / 2) >=1/(x + 1/x)
for $0 < x < 1.$
This is the original problem. I'm trying to prove an intermediate inequality sqrt((2x^2 - 2x + 1) / 2) >= 1/2 >= 1/(x+1/x) .
I used AM-GM on x + 1/x, and I ended up with 1/(x + 1/x) <= 1/2.
Now, I'm kind of having trouble finding a way to prove that sqrt((2x^2 - 2x + 1) / 2) >= 1/2. I don't know if I should use a mean inequality or what to do. I'm so close to solving this problem, so any strong hints would be appreciated.
Thank you so much!!!
So, is it decreasing??? There's not a line in the graph that increases although I'm not sure.
Also, I was wrong about the graph being neither even or odd, and not invertible either. Not sure what I did wrong.
Sorry...
Thanks anyway
I see that for every interval, as x increases, the graph decreases. And, at every whole number, the graph just starts over and decreases again. Thanks so much for the graph!!!
Ok, so I think the graph is neither even or odd, and not invertible either. I'm not sure if it's increasing or decreasing though....
I cannot thank you enough! Thanks!
Define {x} = x- \lfloor x\rfloor. That is to say, {x} is the "fractional part" of x. If you were to expand the number x as a decimal, {x} is the stuff after the decimal point. For example {3/2} = 0.5 and {\pi} = 0.14159...
Now, using the above definition, determine if the function below is increasing, decreasing, even, odd, and/or invertible on its natural domain:
f(x) = \lfloor x \rfloor - {x}
I'm kind of stuck on this one as I usually use a graph to help me determine if the function is increasing, decreasing, even, odd, etc. (oops, I know it's not a very reliable way) and for this one I have no idea what the graph would look like because of that floor function. How should I do this problem?
Any help would be appreciated! Thanks!
@rileywkong Haha, thanks. I actually ended up using those triangles instead because the solution was shorter and easier in my opinion.
Oh yeah... ok THANKS SO MUCH!!!
How do we know triangles SAQ and SDR are similar? (I hope I have my diagram correct) So, is SR a straight line and if it is, how do we know that? To be clear, point S is created when we extend CP and AD right??? Thank you in advance!
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