You are not logged in.
Pages: 1
That's what I wanted to find. The automated solution is perfect.
Only instead of using Mathematica (don't have it here at home), I used WolframAlpha online.
But it worked.
For other similar cases as well.
Thank you!
Nice, this equation does the job as I wanted.
If you could share the method you use I would really appreciate.
thanks
Ok, thank you very much!
I'll check if I find a way with Mathematica.
If you come with a method I'd be very pleased to see it, and try to apply it to other cases.
Not exactly. What I mean is:
R(1) = TA-S
R(2) = (TA-S)*T-S
R(3) = ((TA-S)*T-S)*T-S
Sorry if I expressed it wrong.
Sorry about the misnaming.
The equal sign wold be the "result" of the polynomial. (Let's call it "R").
Then it wold be like this:
R(n)=((((A*T)-S)*T-S)*T-S).... for n times
and what I wanted to find is this form:
Because this form is much easier to solve for high values of n.
Thanks
Hello,
I'd like to know how do I transform a serie that repeats n times into an equation.
For example:
Serie: ((((A*T)-S)*T-S)*T-S).... for n times.
For this example i know the equation is:
T^n*A-S*(T^n-1)/(T-1)
What method can I use to do this transformation?
Is there a software that can do this?
So far I'm using Excel and using a formula for n lines to get the result.
Thanks!
Pages: 1