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#1 Re: Help Me ! » A challenge for Coders/programmers » 2021-02-03 00:54:01
Then tell me one solution to this equation!
#2 Re: Computer Math » Brute force for diophantine equation » 2021-02-02 20:42:40
Thank you for your kind reply ?
#3 Re: Computer Math » Brute force for diophantine equation » 2021-02-02 04:08:45
Thanks a lot
But can I send you a msg in your mail to discuss more about coding and brute force? If you don't mind
#4 Re: Computer Math » Brute force for diophantine equation » 2021-02-01 22:30:26
Hi sonu1997 & irspow;
I also tried, and failed...but that doesn't mean much!
I wonder if the equation's been entered correctly, though.
The reason I ask is that in case the trailing constant (which I'll call 'c') happens to be wrong, I tried a range of alternatives for c...with some success:
Using Mathematica, I found 31 solutions for {x,y,z}, subject to the following constraints:
1. x = between -100 & 100
2. y = between -100 & 100
3. c = between 100 and 999, containing at least two digits of the OP's '114' in their correct positions (in case c contains just one incorrect digit).Three examples of my solutions:
(a) x = 7, y = ±48, z = 46, c = 118
(b) x = 10, y = ±69, z = 66, c = 164
(c) x = 5, y = ±4, z = 6, c = 514
Hlo phrontister,
Thanks for your efforts but let me tell you it is suspected that the magnitude of the solution is extremely large may be more than 15 digits so I'm sure you will never find any solution in between the range -100 ad 100 or even millions?
If you don't mind can I mail you?
#5 Re: Computer Math » Brute force for diophantine equation » 2021-02-01 22:27:03
Don’t feel bad. I was leery when I saw the trailing constant of 114 which has no rational cube root. Just for kicks I threw that equation into mathway and wolfram alpha, the two giants of online calculators. Neither of them could produce any rational solutions for z much less an integer.
No it's ok atleast you tried though. The solution happens to be very difficult
#6 Help Me ! » A challenge for Coders/programmers » 2021-01-28 23:48:20
- sonu1997
- Replies: 2
2x³+6xy²-114=z³
Crack down this one by brute force
A challenge for coders
x,y,z are must be integers
Best of luck?
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