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Hi (Temporary username),
Neat work!
#5491.
Hi,
#5490.
Edited.
i found a broken latex post,
x^{2}+y^{2}=100\ \left\{x<10-\frac{y}{\sqrt{3}}\right\}\left\{y<\frac{159}{16}\right\}\left\{14x+8y>-160\right\} x^{2}+\left(y+7\right)^{2}=5 \left(x-6\right)^{2}+\left(y+4\right)^{2}=5 \left(x-15\right)^{2}+\left(y-5\sqrt{3}\right)^{2}=100\left\{x<10-\frac{y}{\sqrt{3}}\right\} x^{2}+\left(y-8\right)^{2}=5\ \left\{y<\frac{159}{16}\right\} \left(x+6\right)^{2}+\left(y-4\right)^{2}=5 \left(x+7\right)^{2}+\left(y+4\right)^{2}=5\left\{14x+8y>-160\right\} x^{2}+y^{2}=18 x^{2}+\left(y+2\right)^{2}=4 \left(x-3\right)^{2}+\left(y-3\right)^{2}=4 \left(x+4\right)^{2}+y^{2}=4 y=2x+8\left\{-5<y<6\right\}\left\{\left(x+7\right)^{2}+\left(y+4\right)^{2}>5\right\} \left(x+y-7\right)\left(x+y-8\right)=0\left\{x^{2}+\left(y-8\right)^{2}>5\ \right\}\left\{\left(x-3\right)^{2}+\left(y-3\right)^{2}>4\right\}\left\{4<y<8\right\} \left(x-2\right)^{2}+\left(y+6\right)^{2}=0.25 \left(x-7\right)^{2}+\left(y+2\right)^{2}=0.25 x^{2}+\left(y-8\right)^{2}=0.25 x=0\left\{8.5<y<12\right\} \left(x+6\right)^{2}+\left(y+9\right)^{2}=0.25 \left(x-3\right)^{2}+\left(y+4\right)^{2}=0.25 \left[\left(-6,5\right),\left(-5,3\right),\left(-7,3\right),\left(-3,1\right),\left(-3,-1\right),\left(0,-1\right),\left(1,-3\right),\left(-1,-3\right),\left(1,-7\right),\left(-1,-7\right),\left(0,-6\right),\left(0,-8\right),\left(6,-3\right),\left(7,-5\right),\left(5,-5\right),\left(6,6\right),\left(7,4\right),\left(8,3\right)\right] x^{2}+y^{2}=144 x^{2}+y^{2}=160
I couldn't fix it
Latex won't show normally if it's really long.
i found a broken latex post,
I couldn't fix it
Pages: 1