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umm..guys, what if there are 2mangnolias, 3 figs and 4 prunes trees. What is the probability that 2 magnolias are on the opposite sides of the road. (1 must be north, another must be south)...any idea??
A secret code that needs to be key-ed in using only 1,2,3,4,5 button. If to open the door, u need to press three buttons, how many possible ways there to open the door? Assume tat the same code may be repeated.
For now, i have to ways in mind...it's either
5 x 5 x 5
OR
1st condition- all numbers are different = 5p3
2nd condition- 2 num r de same, 1 is diff = (3p3/2p2) x 4
3rd condition- all num r de same = (3p3/3p3)
and add all the answers together..
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i'm nt sure which would b a better way..or the correct way..pls help..
hurm...mathsyperson..i dun really get ur way...but i was thinking
(2! x 7!)/9! according to the probability formular = n(A)/n(S)
what u guys think?
Hi guys,
I have a question here which is really causing me headache. Hopefully, someone could help me with this
The positions of nine trees which are to be planted along the sides of a road, five on the north side and four on de south side.
O O O O O ---North
O O O O ---South
So, the first question is:
Find the number of ways in which this can be done if the trees are all of different species.
ANS: what i have in mind is this... 9P5 x 4! coz first one gotta pick 5 out of the nine to arrange 1st and then the balance will be 4!
next question will be:
If the trees in the above question are planted in random, find the probability that two particular trees are next to each other on the same side of the road.
ANS: the prob I have is that I dunno if i should treat each tree as unique or not. So far, what I have in mind is this:
(4! x 2! x 4!)/(9P5 x 4!) + (3! x 2! x 5!)/(9P5 x 4!)
I'm nt sure if this is right or not...
Pls do correct me if i'm wrong..THANKS A MILLION!!!
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