Math Is Fun Forum

you  make it on the perpendicular ??!

thank u Bob I was about 2 lose hope but why did u impose that The point (x,y) is where a line from (1,4) meets the line of action of F at 90 degrees? Sorry for bothering u

many thnx John I didn't know How I missed cosine law

thanks for ur reply I appreciate it . I think that this is the right solution , I have been searching for a related time problem like this one but I found none but at the same time I didn't think that the sol might be that easy one.The textbook is my school book and we're in secondary school so the ministry in our country  prepare it without writing the references. Many Thanks

we don't solve it that way it is unofficial in our curriculum to solve it using derivative we use these rules http://library.thinkquest.org/C006002/Pages/Rules_of_Limits.htm

many thnx highly appreciated

multiply it by the conjugate then divide each term under the cubic root by x^3 and out the root by x

Actually I didn't study it that way am in high school so we learn only headlines Thnx 4 ur help

SORRY I'd mistaken the sign preceding 1 in the numerator
my Mr solved it for me today
F(x)=x^2-x+1/(x+1)(x^2-x+1)=1/x+1
http://www.mathsisfun.com/data/function-grapher.php?func1=(x^2-x-1)/(x^3+1)&xmin=-12&xmax=12&ymin=-8&ymax=8
Domain=R-{-1}
Range=R-{0}
Decreasing in (-∞,∞)-{-1}
am very sorry for that stupid mistake i had made