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#1 Help Me ! » Mechanics - Energy, work and power » 2010-06-09 22:05:08

cathelyn13
Replies: 1

The driving force exerted by D's engine is 4 times as great when D is at the top of the hill as it is when D is at the bottom. Find the ratio of the power developed by D's engine at the top of the hill to the power developed at the bottom.

Thanks in advance!! smile

#2 Help Me ! » Mechanics - Newton's law of motion » 2010-06-04 19:32:16

cathelyn13
Replies: 1

Particles of masses 0.7kg and 0.3kg are attached to the ends of a light inextensible string which passes over a smooth pulley. The system is released from rest and the particles move vertically.
i) Find the tension in the string
ii) State the magnitude of the resultant force exerted on the pulley by the string.


Thanks in advance!!! smile

#4 Re: Help Me ! » Integration by substitution » 2010-04-01 02:31:38

Thanks! But won't I get answer in terms of sin x if I use x = sin x as substitution? smile

#5 Help Me ! » Integration by substitution » 2010-04-01 00:33:35

cathelyn13
Replies: 3

Please help me to solve this question.

Use suitable substitution to find the following integral: (1 – x^2)^(-3/2)dx

The answer provided is x/(root 1-x^2) + k

Thanks in advance!!! smile

#7 Re: Help Me ! » Question on Normal Distribution » 2009-07-18 05:15:22

I see. Thanks a lot!! smile Should be it. Hehe! smile

#8 Re: Help Me ! » Question on Normal Distribution » 2009-07-18 02:57:42

It's Advanced Level Mathematics Statistic 1 by Steve Dobbs & Jane Miller. smile

#9 Help Me ! » Question on Normal Distribution » 2009-07-18 01:33:07

cathelyn13
Replies: 5

The fluorescent light tubes made by the company Well-lit have lifetimes which are normally distributed with mean 2010 hours and standard deviation 20 hours. The company decides to promote its sales of the tubes by guaranteeing a minimum life of the tubes, replacing free of charge any tubes that fail to meet this minimum life. If the company wishes to have to replace free only 3% of the tubes sold, find the guaranteed minimum it must set.

What I did was:
Let A be the minimum number of hours,
(A - 2010) / 20 = -1.8808
A = (-1.8808 * 20) + 2010 = 1972.384
So my answer is 1972 hours. However, the answer provided by the book is 1970 hours but I only can get 1972.384.. If anyone can get 1970, how did you arrive to that answer?

Thanks in advance!!  smile

#10 Help Me ! » Integration Application: Volume generated by area bounded by two curve » 2009-07-18 01:18:03

cathelyn13
Replies: 2

Q: Find the volume generated by area bounded by two curves rotated through 360 degrees about the y-axis:
a) y = x²
y = 2- x²

b) y = x2
y2 = 8x

For these two parts, which formulae should I use?

Volume generated

= π ∫ x² dy
or = π ∫ [f(y)]² – [g(y)]² dy ?


For part a, it will be simplier if I use the first formula where I simplify the y before using the first formula:

y = 2 - x² - x²
y = 2 - 2x²
x = √ (2 - y)/2

After using the first formula, my answer is π.

However, if I use the second formula, I got diferent answer:

y = x²
x = √y

y = 2 - x²
x = √(2 - y)


V = π ∫ [f(y)]² – [g(y)]² dy
= π ∫ [√y]² - [√(2 - y)]² dy
= .....
= π (4 - 4)
= 0

For part b, it seems that I can't use the first formula, as after simplify,
y = √(8x) - x²
it's hard to change to make x the subject in terms of y.

Using the second formula for part b, I got the answer 24/7π.

So how do we know which formula to be used for which question? Because the question is involving volume generated by area bounded by two curves, shouldn't we be using the second formula only? Why using both formulas I get different answers? Please help me check if my answer is correct.

Besides I just knew I can use the shell method but I am more familiar with the disk method? Which formula should I be using and why the answer differs if I use both the methods I mentioned?

Many thanks in advance!! smile

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