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#1 Help Me ! » inequality » 2009-10-07 23:15:08

mp3qz
Replies: 1

Prove if x,y,z>0 then:   

#2 Help Me ! » help help inequality » 2009-10-02 23:15:57

mp3qz
Replies: 0

x,y,z>0 & xyz=1
prove

#3 Re: Help Me ! » Inequality » 2009-09-09 21:20:15

mp3qz

but my teacher said : "=" has appear.

#4 Help Me ! » Inequality » 2009-09-08 18:06:17

mp3qz
Replies: 9

1./    SOlve for min & max of:
gif.latex?\;y=\sqrt{sinx+tanx}+\sqrt{cosx+cotx}


[2./   img]http://latex.codecogs.com/gif.latex?x\neq&space;y\neq&space;z[/img]
Demonstrate
gif.latex?\left&space;(\frac{x-y}{y-z}&space;\right&space;)^2+\left&space;(\frac{y-z}{z-x}&space;\right&space;)^2+\left&space;(\frac{z-x}{x-y}&space;\right&space;)^2\geq&space;5

#5 Re: Help Me ! » trig equation » 2009-07-23 16:18:56

mp3qz

juriguen, z=?? or an exact result for x

#6 Help Me ! » trig equation » 2009-07-22 02:01:29

mp3qz
Replies: 5

#7 Help Me ! » trigonometric equation » 2009-07-21 16:14:16

mp3qz
Replies: 1

#8 Help Me ! » Help me inequality » 2009-07-21 14:57:57

mp3qz
Replies: 2

x,y,z >0 & xyz=1 Find min of
gif.latex?P=\frac{1}{x^3(y+z)}+\frac{1}{y^3(x+z)}+\frac{1}{z^3(x+y)}

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