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#1 Re: Help Me ! » second try 2=3.41 » 2009-10-21 01:37:54
hi bobbym
It's ok i understand now but im happy i got as as close as i did since i havent finished high school yet
but thank you for pointing out the flaw now that i know it i can see if my teacher believes it and if my teacher can point out the flaw.:P
thanks anyway bobbym
p.s if you gave me two dollars i would prove in a practical way that 2 = 0 
#2 Re: Help Me ! » second try 2=3.41 » 2009-10-21 01:25:55
Hi saundo;
Sorry, I wished that were true. Would make a lot of my work more meaningful. Unfortunately it is not, this is correct:
√(x^2 )=√(y+x)
this is not:
√x^2=√y+√x
ah i didnt put those brakets in but try these
x=2 y=2
x=y
x^2=y+x
√x^2 =√y+x
x=1.41+1.41
x=2.82
2=2.82
or
x=2 y=2
x=y
x^2=y+x
√x^2 =√y+x
x=1.41+1.41
x=2.82
1.41=2.82
#3 Re: Help Me ! » second try 2=3.41 » 2009-10-21 01:13:51
Hi saundo;
But you cannot separate them. The rules of algebra have to be adhered to.
im pretty sure there is another rule that what you do too 1 side you do to all parts of the other which means that √x^2=√y+√x thus proving my first equation 2=2.82 correct
#4 Re: Help Me ! » second try 2=3.41 » 2009-10-21 01:02:45
Hi saundo;
line 4 to 5 is incorrect. When you take the square root of both sides in line 4 you should get:
√(x^2 )=√(y+x)
that is why they were seperate √(y)+(x)
#5 Help Me ! » second try 2=3.41 » 2009-10-21 00:46:50
- saundo
- Replies: 9
i have proven not that 1=2 but that 2=3.41 i am only 16 but im pretty sure there are no faults in this. what i did and expalnations on how are written below
x=2 y=2
x=y
x^2=y+x
√(x^2 )=√(y)+(x)
x=1.41+x
2=1.41+2
2=3.14
line1 x=2 y=2
line 2 therefore x=y
line 3 add x to both sides( since x=2 and 2+2 Is the same as 2^2 it become x^2)
line 4 square root both sides of the equation
line 5 we are left with x=1.41+x because √2 is 1.41 to 2 decimal places
line 6 substitute the pro-numeral x with the its value (2) leaves us with 2=1.41+2
line 7 the answer is 2=3.41
find any faults now?
#6 Re: This is Cool » proof that 2=2.82 thus that algebra has a huge fault » 2009-10-21 00:34:18
the problem is between line4 and 5. You cannot distribute the square root, i mean,
To my knowledge there is no way to decompose a square root
for some reason the brackets did not come up properly
#7 This is Cool » proof that 2=2.82 thus that algebra has a huge fault » 2009-10-20 20:36:32
- saundo
- Replies: 7
i have proven not that 1=2 but that 2=3.41 i am only 16 but im pretty sure there are no faults in this. what i did and expalnations on how are written below
x=2 y=2
x=y
x^2=y+x
√(x^2 )=√(y)+(x)
x=1.41+x
2=1.41+2
2=3.14
line1 x=2 y=2
line 2 therefore x=y
line 3 add x to both sides( since x=2 and 2+2 Is the same as 2^2 it become x^2)
line 4 square root both sides of the equation
line 5 we are left with x=1.41+x because √2 is 1.41 to 2 decimal places
line 6 substitute the pro-numeral x with the its value (2) leaves us with 2=1.41+2
line 7 the answer is 2=3.41
find any faults now?
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