You are not logged in.
Pages: 1
Integrating a line equation gives the area below the curve (or line). The equation for the first quadrant is:
y = √r²-x²Integrating this equation from zero to r gives:
x/2 (√r²-x²) + r²/2 (arcsin x/r) = πr²/4
Since this is only the area of one quadrant, you must multiply this by 4 which gives πr²
Hi guys
Sorry to resurrect this thread but I really need to be able to derive the formula for the area of a circle using integration and I can't find anything useful on the internet. Please could you explain how it works without missing stages out so it's easier to follow. How do you integrate the "r"? I can't remember!
Thank you so much.
Pages: 1