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Hey Bobbym, can you please elaborate on what you are doing? It sounds interesting
Thanks for the post Jane, I'll look into it!!
But I've managed to solve the problem with triple integrals
Ok, so I'm required to set up and solve an iterated triple integral so find the volume of the solid G that is enclosed by the plane z=y, the xy-plane and the parabolic cylinder y=1-x^2.
How on earth do you find these limits! If It's possible could someone give an analytic approach opposed to a geometric one. I find that once I can do things analytically then I find it easy to learn the geometric way! (if this makes sense at all )
Cheers in advance all
Oh my God facepalm!!! For some reason I thought
Ahh cra.p sorry guys epic fail there!!
Sorry to waste your time guys! argh!
Hi I am required to find the following iterated integral by converting to polar coordinates
This is what I've done so far...
Now what do I do?? Can you simplify the integral to...
Or is there some other neat way of doing it?
Cheers guys!!
Haha I'll try my best=)
Yeah all good, just working my way through chapter 15.3 then will be moving onto 15.5 & 15.7
Ahh well when i differentiate
Use a double integral in polar coordinates to find the area of the region enclosed by the rose
However I don't think this is correct since it seems to be the same area as the circle with r=1. Can someone please tell me where I've gone wrong? (Also Anton says It's wrong )
Cheers for the help!
Yeah It's a beast of a question but managed to get it out after seeing the working for computing for dz/dx
The full question: Show that the function
satisfies Laplace's equation
Then make the substitution
and show that the resulting function r and theta satisfies the polar form of Laplace's equation
Thanks everyone for your replies, I can now do the rest of the question
Hi can someone please show full working on how to get the first derivative(with respect to x) of Z=arctan(2xy/(x^2-y^2)) Thanks!! By the way this is to help me solve question 60 of chapter 14.5 in Anton Calculus 7th edition (can refer to this if you have it) Cheers guys/gals!
Hey guys just a quick question.
Suppose that r(t) = (kcos(wt), ksin(wt))
Is the position vector of a particle rotating around the origin in a circle of radius k and angular velocity w.
Show that the acceleration of the particle is directed at the origin , with magnitude v^2/k, where v is the
speed of the particle
Can someone please go through this, thanks for the help
ok excellent, cheers for the help, also what level of education do u have atm? just curious
Ah ok, so final answer would then be: dz/dt = (1/2)sinh(te^t)[e^t + te^t] ?
that was x = (t/2)
Just a quick problem... My solution was 0, just making sure this is correct
z=(cosh(xy))^2 ; x=(t/2) , y=e^t Find dz=dt
Thanks for the reply
Also, would that make ¬(B ∨ D) equivalent to (¬B ∧ ¬D)
Hey guys.
A for Min is at home
B for Min is on board
C for Henry is at home, and
D for Henry is on board.
For...
(iii) Either both Min is on board and Henry is on board or neither is on board.
I was wondering whether (B ∧ D) ∨ (¬B ∧ ¬D) [ model answer ] is the same as (B ∧ D) ∨ ¬(B ∧ D) [my answer]
This may be really obvious but i'm just making sure cheers for the help guys
Woops, was trying to figure latex and accidently pressed enter, sorry
[math]\pi(n) = \sum_{m=2}{n}
math]
A parabola is given by y^2=4ax and the ellipse (x^2)/a^2 + (y^2)/b^2 = 1 where a>0 and b>0, meet at the points P and Q.
(a) The two curves intersect in such a way that the tangent to the parabola at P is perpendicular to the tangent tothe ellipse at P.
(i) Show that B^2 = 2a^2
(ii) Hence, find in terms of a, the distance of the point P from the origin O.
(b) The tangent to the parabola at P meets the x-axis at M. The tangent to the ellipse at P meets the x-axis at N. Show that the length of MN=(2*(sqrt)(2))a.
Hi guys, I have solved (a), but am having problems with (b) I was wondering if anyone can show a full solution using a parametric method. i.e. using (at^2,2at) for the parabola and dy/dx=(1/t) if that helps. Cheers
OK having problems with this one: Find the gradient of the normal to the curve 2xy ² -x²y³ =1 at the point (1,1)
Thanks in advance!
Thank you!