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I am solving ten problems that all are suppose to result in a single digit answer. One of the problems is stated as such
"n! means n × (n-1) × (n-2) ... × 3 × 2 × 1
Find the sum of the digits in the number 100!
Then:
subtract 3 from this value to get your answer"
I computed 100! to be the 158 digit numer 9332262..... and the sum of the digits 9+3+3+.... to be 648. So 648-3=645. As I said, this is suppose to end up a single digit. I have asked the author the same question, but he would not surrender any clues. Am I missing some kind of riddle/brainteaser in how the problem is stated?
Thanks.
Pages: 1