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i) Geometric
X~Geo(1/3)
E(X) = 1/(1/3) = 3
VAR(X) = q/(p^2) = (2/3)/(1/9) = 6
ii) Binomial
X~B(7, 1/6)
E(X)=7(1/6) = 7/6
VAR(X) = 7(1/6)(5/6) = 35/36
iii) Looks like it'll be a Binomial but more info is needed such as the number of marks but P would be 1/2
iv) Same as iii
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