You are not logged in.
Pages: 1
no of possitive roots = the no of times sign is changed in the eq f(x)
and no of negative roots = the no of times sign changes in eq f(-x).
so for the given eq. +ve root = 2
and -ve root =
f(-x)= x^4 + x^3 -3x^2 +x +2=0
so -ve root = 2
sorry but i was not able to get ur ques. could explain it plz
both
well for c program you can just use simple looping concept
like
sum=0;
for(i=n;i>=0;i--)
{
sum=sum+pow(x,i);
}
isn't it simple?
is that helped you or you did it in another way?
how can it be sure as s^2t itself is multiple of 7, i think atleast it should be s^4t.
is it necessary for simle things to make it on difficult way it is as simple as nCr like so take a right step. definately it will increase the way of thinking for big nos.
thanks guys it helped me a lot but one more thing puzzled me ? the significanse of 2/7 ? well it is not a random one.
what is the fastest way to compute???(i.e. factorial of 285714)???
help me please. what is the fastest way to compute 285714! (i.e. the factorial of 285714)?
Pages: 1