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#1 Re: Help Me ! » question » 2006-12-30 04:20:43

no of possitive roots = the no of times sign is changed in the eq f(x)
and no of negative roots = the no of times sign changes in eq f(-x).
so for the given eq. +ve root = 2
and -ve root =
f(-x)= x^4 + x^3 -3x^2 +x +2=0
so -ve root = 2

#2 Re: Help Me ! » solve » 2006-12-29 03:30:55

sorry but i was not able to get ur ques. could explain it plz
both

#3 Re: Help Me ! » Expressing # of different character combinations for a given character » 2006-12-29 03:27:38

well for c program you can just use simple looping concept
like
sum=0;
for(i=n;i>=0;i--)
{
      sum=sum+pow(x,i);
}
isn't it simple?
is that helped you or you did it in another way?

#4 Re: Help Me ! » can yu make this question complete . justify! » 2006-12-29 03:08:57

how can it be sure as s^2t itself is multiple of 7, i think atleast it should be s^4t.

#5 Re: Help Me ! » two player » 2006-12-29 02:51:05

is it necessary for simle things to make it on difficult way it is as simple as nCr like so take a right step. definately it will increase the way of thinking for big nos.

#7 Re: Help Me ! » 285714! » 2006-12-28 17:10:44

thanks guys it helped me a lot but one more thing puzzled me ? the significanse of 2/7 ? well it is not a random one.

#8 Help Me ! » 285714! » 2006-12-27 04:15:55

er.neerajsrivastava
Replies: 23

what is the fastest way to compute???(i.e. factorial of 285714)???

#9 Re: Help Me ! » endpoints » 2006-12-27 04:13:17

help me please. what is the fastest way to compute 285714! (i.e. the factorial of 285714)?

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