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#1 Re: Help Me ! » Geometric or algebraic problem...I don't know » 2008-02-16 07:51:56
Please help me...-.-
I'm desperate...
#2 Re: Help Me ! » Geometric or algebraic problem...I don't know » 2008-02-09 21:58:21
...-.-
#3 Re: Help Me ! » Geometric or algebraic problem...I don't know » 2008-02-06 04:24:03
Can nobody help me...-.-?
#4 Re: Help Me ! » Geometric or algebraic problem...I don't know » 2008-02-04 04:02:46
Did someone found out s.th. helpful or anything else at least?
#5 Re: Help Me ! » Geometric or algebraic problem...I don't know » 2008-02-03 01:48:32
Okay, I understand what you are saying. I think it's helpful, so one only has to prove by using this finding such moves are impossible to get to the set.
#6 Re: Help Me ! » Geometric or algebraic problem...I don't know » 2008-02-03 01:05:12
Hi.
What you wrote seems to be logic. However, I don't understand what you mean by parity. Could you enlarge on that?
#7 Re: Help Me ! » Geometric or algebraic problem...I don't know » 2008-02-02 13:07:58
Yeah, you are right.
However, I have tried it quite intensively, I tend to say it is not possible. I am just lacking a proof as I cannot just say I didn't manage to move them...
#8 Re: Help Me ! » Geometric or algebraic problem...I don't know » 2008-02-02 10:14:26
Hmm, Jane, the method seems to be interesting, however, there are infinite possible final moves...
Moreover, how can I prove a certain move is impossible?
#9 Re: Help Me ! » Geometric or algebraic problem...I don't know » 2008-02-02 10:12:37
Yes, they are, as long as they don't break the rule: To reposition a point, there must be another point exactly in the middle between the new and the old position. Therefore diaganoal moves are allowed.
#10 Re: Help Me ! » Geometric or algebraic problem...I don't know » 2008-02-02 09:31:15
Do you understand the task?
#11 Re: Help Me ! » Geometric or algebraic problem...I don't know » 2008-02-02 08:26:58
I cannot upload any images...
#12 Help Me ! » Geometric or algebraic problem...I don't know » 2008-02-02 08:20:56
- Thomas11
- Replies: 15
Hi, I really need your help. My Maths teacher wants me to do a presentation on the follwoing problem to improve my Maths mark. I just don't know how to do that task. Please help me.
There are 4 points on a plane coordinate system.
These points have the following coordinates:
1.(0;0)
2.(1;0)
3.(0;1)
4.(1;1)
These 4 points are to be repositioned.
You may only reposition points in the following way:
You may only change the position of a point, if there is another
point exactly in the middle between the original and the new
position of the point.
Now, I have to prove whether or whether not it is possible to
reposition the points, in order to get the following coordinates:
1.(0;0)
2.(1;1)
3.(2;-1)
4.(3;0)
I've tried this little game quite intensively and I'm sure it is impossible but I still can't prove it.
#13 Help Me ! » Geometric or algebraic problem...I don't know » 2008-02-02 08:18:33
- Thomas11
- Replies: 0
There are 4 points on a plane coordinate system.
These points have the following coordinates:
1.(0;0)
2.(1;0)
3.(0;1)
4.(1;1)
These 4 points are to be repositioned.
You may only reposition points in the following way:
You may only change the position of a point, if there is another
point exactly in the middle between the original and the new
position of the point.
Now, I have to prove whether or whether not it is possible to
reposition the points, in order to get the following coordinates:
1.(0;0)
2.(1;1)
3.(2;-1)
4.(3;0)
#14 Re: Help Me ! » Geometric proof wanted (triangle, bisector) » 2007-02-15 03:17:23
Help me...-.-
#15 Re: Help Me ! » Geometric proof wanted (triangle, bisector) » 2007-02-10 05:22:09
Uh, please inform me, even if you only find s.th. that might be helpful, I'll appreciate your efforts.
#16 Re: Help Me ! » Geometric proof wanted (triangle, bisector) » 2007-02-06 03:31:07
Has anybody found s.th. interesting or helpful yet? (me not -.-')
#17 Re: Help Me ! » Geometric proof wanted (triangle, bisector) » 2007-02-02 23:03:20
Hello, that is my problem:
There is a triangle ABC. On the side AC there is a point E and on the side BC there is a point F. Besides you must notice that the line segment AE is as long as the line segment BF. So: AE=BF
Then one examines the circumscribed circles of the two triangles, which are a part of the triangle ABC, AFC and BEC. These circumscribed triangles subtend each other at the point C and at another point D. Finally it is to prove that the line segment with the starting point C and the ending point D is the bisector of the angle gamma (the angle at the point C).Please help me, I am nearly desperate... I just don't know how tpó proof this...
Now the picture matches the exercise, I named s.th. wrong. Now it should be right.
#18 Re: Help Me ! » Geometric proof wanted (triangle, bisector) » 2007-02-02 13:07:28
Stanley_Marsh wrote:What? how can the segment CF besect any angle? Name the angle gamma ,I don't really understand ,lol
Segment CF bissects angle gamma.
It's segment CD. Segment CF is a part of the triangle side a. Have a look at the picture. 
#19 Re: Help Me ! » Geometric proof wanted (triangle, bisector) » 2007-02-02 07:26:02
Did the picture help you to understand my problem?
#20 Re: Help Me ! » solve system by addition » 2007-02-02 03:09:21
Here's the solution:
2x+3y=1
5x+3y=16 | 3x=15, x=5
5*5+3y=16
25+3y=16
3y=-9
y=-3
x=5
y=-3
#21 Re: Help Me ! » Geometric proof wanted (triangle, bisector) » 2007-02-01 22:44:20
Here's a picture of the problem
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