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hi, Apart from inequality is this similar to the form whch i hv written whch is
ln(x) = x +constant
and wht is Hx? is this constant?
Bobbym thank u so much for tryin it. I ll thnk over it
i want to ask
is this some identity ln(x) = x +constant ?
Yes, u can still assume x and z are beween range of 0 to 1.
y can be 0 or 1. this is only info i have abt y
ok... NO PROBLEM. I LL BACK TO YOU IN 2 HOURS. I HOPE TILL THEN WE ACHIEVE DESIRED RESULT. I KNO ITZ HARDER. ESPECIALLY WHEN U DONT KNO ALL D DETAILS.
BUT STILL PLEASE TRY TO DO.... CHEERS!
Yes, The Problem Is Same What U Have Wriiten.
Thank U So Much For Trying It
Please Try To Reach Required Form. I Am Only Left With This Part Of The Project.
Cheers!
according to my project. it is required
if we do derivative of F(x, y) w.r.t y and equate it to 0 then it yields as follows:
ln (x*z / y) - x*z / y = __?___ ..............(2)
and i want to derive 2nd equation from it. please solve it.
and there is third term as well. An exact problem is as follows:
F(x, y) = ∑1 ∑2 y log2(1+ x*z/N*B* y) + c*(∑2 x -r) + a *(∑1 y 1)
∑1 represents summation ranges from p=1 to P
∑2 represents summation ranges from q=1 to Q
x, y and z are functions of p and q
'c' is a constant like 'a' and 'r' is another variable.
previosly i hvnt included c*(∑2 x -r) because i thought it wil be zero, when we do derivative of F(x, y) w.r.t y
i have given you exact problem now.
ok... sory for any inconvenience i created. i thought we can leave sigma for derivatives.
my problem is like that wht u hv written. only difference is of sigmas. rest of the things are same
BUT, in 2nd term there is costant 'a' as well it is like a*(∑1 y 1) and summation is only for y, 1 is not included in summation.
please try to solve it soon. as i hv deadline tomorrow.
yes, we are not goin to put values in this equation. that y in the denominator is nt a problem for my project
please help me out wd this equation
I also want to know do derivation rules chnages with summation. i mean wd dis symbol ∑
becuase the original equation is
F(x, y) = ∑1 ∑2 y log2(1+ x*z/N*B* y) + a *(∑1 y 1)
∑1 represents summation ranges from p=1 to P
∑2 represents summation ranges from q=1 to Q
x, y and z are functions of p and q
y can only take two values either 0 or 1
Sory in previous post, i hv written wrong. Actualy, x and z are variabes ranging between 0 to 1.
y can be 0 or 1. while others are variables. x and z are variable less than 0
Hi bobbym...
i dnt wnt variables at RHS. anyways you solve it the best you can. please drive LHS same as required. we can c RHS later on
Thanks
In equation (3), Left hand side is also different, that is why i put minus sign at the right hand side
hi bobbym... equation (3) is modified from ur equation. I have rearranged it.
you please try to rearrange it to the required form.... if we dnt get constant at right hand side... dunno wry.... u please bring it to the required form by any means.
Thanks
thanks bobbym...
actualy i want exact solution as equation 2
the solution that you have given is like as follows
ln((x*z+BNy)/BNy)-x*z/(BNy+xz)=-aln(2)
we can leave BN according to my project, So now above equation becomes
ln((x*z+y)/y)-x*z/(y+x*z)=-aln(2) ....(3)
Now from above equation (3), i want to derive equation (2), left hand side should be same as in equation(2).
equation(2) is ln (x*z / y) - x*z / y = __?___
please try to solve my problem. thanks!
thanks... i want this equation somewht like equation 2... can u solve it further.
yes, eq(1) is same like this.
x is also multiplied by z in the numerator, rest is fine
please help me as soon as possible. thanks
actually i dont want to solve equation for a specific solution. my problem is different. ok let me try to explain it.
I have this equation.
F(x, y) = y log2(1+ x*z/N*B* y) + a (y 1) ...........(1)
if we do derivative of eq (1) w.r.t y and equate it to 0 then it yields as follows:
ln (x*z / y) - x*z / y = __?___ ..............(2)
i want to find right hand side of equation (2), i know it is some constant but it is exactly equal to what? i want to find that. please help me out.
thanks..
thanks bobbym... can u also tell me wht is the formula to sove ln(x+y)
i mean how cn v open above equation like ln(xy)=ln(x)+ln(y)
wht is ln(x+y)=?
YES, i HAVE USED THE SAME EQAUTION, GIVEN IN FORUM #50
IS IT OK?
yes, i want to use 2nd one but there is no -ve sign. please see equation in ur forum #33
hi..
but cant i use eqn on forum #33? and can you explain y i cant use it in reference to forum #44
thanks. but i have used following equation in my project
x1=x3W(e^(-a))/x2
which u given earlier. i wanted to kno wht W(e^(-a)=?, if 'a' is positive. wil it b positive?
please help me out.
thank u guys... u tried ur best....and with ur help i achieved some where...... thank u so much... u r doing gr8 job...keep it up.
my prob was just to solve that equation, which is solved by ur given soln as follows:
x1=x3W(e^(-a))/x2
u meant above eqn is same as ln(x1*x2/x3)-x1*x2/x3=a
Am i right?
can u also tell me...what will be lambert function of a (costant). i mean will it be some constant as well?
can u plz also describe why we need to use lambert function as i need to put all this in report.
once again thank u so much!!