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Zhylliolom wrote:
/*But this is no time for sightseeing, we have an equation to derive. Let us consider the known identity(whose proof is left to the reader as an exercise wink)
Zhylliolom wrote:
/*But this is no time for sightseeing, we have an equation to derive. Let us consider the known identity(whose proof is left to the reader as an exercise wink)
Hi, this is my first post. I know that:
Sorry I don't know how to do derivatives in LaTeX.
Can someone help me prove the above statement?
These are two coupled equations, to solve it differentiate both sides, to get:
y''=x'=y
x''=y'=x
The general solution to this, where C and D are constants, is C sinh(t) and D cosh(t). Using your initial conditions:
x(0)=1
y(0)=0
x=cosh(t)
y=sinh(t).
Does this help?
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