Math Is Fun Forum

haha! this is too funny bob's needs help in this and me smileybob need help 2! lol to funny anyways I was wondering if someone could check my work thanks so the question is like so:
The time it takes for a pendulum to complete the one period is simplified by the formula: T=2 pi square root (L/g) Where g is the constant measuring 9.80655m/s^2 and L is the length of the pendulum. The length of the pendulums from a manufacture are normally distributed with a mean of 10cm and a standard deviation of 0.01 cm. Assuming the at a 10cm pendulum gives the correct time, what is the probability that a clock using one of theses pendulums will lose more than 1 minute a day?

so my work so far:

Standard deviation: 0.01cm
Mean= 10cm
T= 2pi [sqrt] L/g
Time increases by: 1/ 24x 60
……
P(x> 10.014)
= p (z> (10.014-10 / 0.01)
= P (Z > 1.4)
Z= 0.919243

But I noticed that you took away 1 from the z right?
Do you think that is necessary here? My next question is this correct?

Best regards
Smiley bob
Thank you!
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