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Here's something to start you off:
P(6)=3P(1), P(5)=2P(2), P(4)=P(3). Let x = P(1), y = P(2), z = P(3). Since probabilities add to 1, we have
x + y + z + z + 2y + 3x = 1, equivalently 4x + 3y + 2z = 1
yes I have the same way of thinking. Now there is the question of amount of cubes...
and i b) part, I have idea, that i will express x, y and z and i will put this into formula Ex = 1*x + 2*y + 3*z + 4*z + 5*2y + 6*3x. Is my idea correct? thx for respond.
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