Math Is Fun Forum

A number of books say we can use the substitution y=(m+1/m) to solve quartic equations that are symmetric i.e equations of the form ax^4 +bx^3+cx^2+bx+a=0, but do not talk much on quartic equations that are not symmetrical and are not easily factorised. The question is, are there other general methods of solving non-factorisable polynomial equations of degree greater than 3?

No news is Good news

He who expects the unexpected is unexpecting the expected

Pls can we keep this section moving by sending more wise sayings?

In my opinion I do think (x,y,z) = [z - g(x,y)]/3 is coorect.Since we shall be integrating

Are you treating complex numbers? If yes, then Z represents a complex number of the form  z= x+yi.
And z/6z=x+yi/6(x+yi).
Rationalise:x+yi(x-yi)/6(x+yi)(x-yi)
                = (x^2+y^2)/6(x^2+y^2)
                 =1/6
NB!!! This is if you saw this under complex numbers.

Thanks ery much> I just discovered there's more in Linear Programming than I thought of.

Two lines are perpendicular if the product of their gradients equals -1
Write each equation in the form y=mx+c:
where m is the gradient.
px+4y-2=0
y=-(p/4)x+1/2......., m1=-p/4
2x-y+p=0
y=2x+p.........., m2=2
m1*m2=-1...., (-p/4)*2=-1....p=2

I'll continue from
where the inv of tan:
sin,cos and tan are +ve at 1st quandrant(angle=@°),sin +ve at 2nd(angle=180°-@),tan+ve at 3rd(angle=180°+@°) and cos+ve at 4th(angle=360°-@°).
Invtan(-1/2)=26.6° and Intan(-3°)=71.6°
Therefore required angles are
(180°-26.6)°, (360-26.6)°,(180-71.6)°and(360-71.6)°
Sorry I don't haveagood programthat illustrate Maths symbols.

Is there any site that has explicit notes on Combinations and Permutations? I'll like  to be versed with that Topic.