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#1 Re: Help Me ! » Who can solve this problem ? I can . How about you????? :) » 2008-01-30 17:46:45
Step by step
*1st method:(JaneFairfax)
Let
we have
It is too long to develop and if you do so you may make some mistakes while you developing .
*2nd method
Let
We have
With this method you dont have to develop any to something
I think that the point that make the 2nd method easier.
#2 Introductions » Hello » 2008-01-30 04:18:07
- phamthephong100
- Replies: 5
This is the first time I introduce myself in a big forum like this
My name is Phong (not Pham )
*First
I'm not an american
I'm not from EU
I'm not from China
I'm from a very little coutry
Can you guess where I'm from
*Second
I love maths ( i dont know why)
I'm not a maths genius I can solve or explain many problems and many things .
I think I'm really smart
*Third
I like sport but only badminton and marathon (are these words right ?)
I like cat
I love video games
I love machines
I love ....(many things) hehe
*Third
If you are my friends you can ask me to help you with any things (only i can)
If you are my friend you will find that I'm a great friend.
If you are my friend you will find that I'm really talkative
If you are my friend you will be impressed of my unbelieveabled ideas (may be crazy !!!)
ANYONE WANTS TO BE MY FRIEND(MAY BE THROUGH EMAIL)
#3 Help Me ! » Who can solve this problem??? » 2008-01-30 03:52:26
- phamthephong100
- Replies: 5
#4 Re: Help Me ! » I Don't Understand This D: » 2008-01-30 03:45:13
the answer depends on the questioner
#5 Re: Help Me ! » Proof by using multiple theorems » 2008-01-30 03:39:53
I think the answer is quite simple
*If A lies => A is a knave =>b is a knight
*If A tells the truth =>A is a knight =>B is a knave
a knave always lies ,B:"A and I are of opposite type." is a lie=> B is a knight ( impossible )
Conclusion: A is a knave and B is a knight
Do you think this is correct ? I can not tell you all the things that i'm thinking -- my English is not good
#6 Re: Help Me ! » how to solve this » 2008-01-30 03:28:26
we can see x^2+2x+3<>o with any x belong to R
let
we have
or
*
* impossible to solve hehe
Please give me your opions about this method
Thanks
#7 Re: Help Me ! » Who can solve this problem ? I can . How about you????? :) » 2008-01-30 03:11:55
if you use y=x+3 ,you have to
(y+1)*(y+1)*(y+1)*(y+1)= y*y*y*y+4*y*y*y+6*y*y+4*y+1(easier ???)
my method
y*y*y*y+(y-1)*(y-1)*(y-1)+(y-2)*(y-2)-2=0
<=>y*y*y*y+ y*y*y-2*y*y-y+1=0
<=>y*y*y*(y+1)-y*(y+1)-(y+1)(y-1)=0
<=>y*y*(y*y+y-1)-(y*y+y-1)=0
<=>y*y-1=0 or y*y+y-1=0
#8 Re: Help Me ! » Who can solve this problem ? I can . How about you????? :) » 2008-01-26 17:30:06
your solution is quite stupid
why dont you let a=x+4 that 's much easier 
:lol::lol::lol::lol::lol::lol::lol::lol::lol::lol::lol::lol::lol::lol::lol::lol::lol::lol::lol::lol:
#9 Help Me ! » Who can solve this problem ? I can . How about you????? :) » 2008-01-18 04:33:16
- phamthephong100
- Replies: 11
(x+2)*(x+2)+(x+3)*(x+3)*(x+3)+(x+4)*(x+4)*(x+4)*(x+4) = 2
x=?????????
show me !!!!!!!
#10 Re: Help Me ! » Physics math » 2008-01-18 04:13:48
1) 0.0876m
2) 400000000 metric tons
100000000 gallons
3) about 1001.875 days
others problems are so that even a primary student can solve all of them .you should solve them by youself
P/S my english is not very good
#11 Re: Help Me ! » Trigonometric Identities » 2007-10-13 17:19:06
too easy
#12 Re: Help Me ! » equationsof a line » 2007-10-13 17:08:17
line (d):y=3x+2 contain the point (r,s) =>s=3r+2
We Have
(3r+2-s)(4r+9-s)=0
<=> s=3r+2 or s=4r+9
==>(1) is sufficient (a)
(4r-6-s)(3r+2-s)=0
<=>s=4r-6 or s=3r+2
==> (2) is sufficient (b)
(a)(b)=> Statements 1) and 2) together are sufficient
I'm not very good at solving problem in English , there may be some mistake
I'm not good at english too
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