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#1 Re: Help Me ! » divide150................... » 2007-10-23 00:35:24

I dont reallt understand your question !

60 -50 -40 ???

#2 Re: Help Me ! » Algebra » 2007-10-23 00:33:21

What was the book?

#3 Re: Help Me ! » Probability: 2 students and 1 professor » 2007-10-22 06:01:21

Ah, right !!!

I was looking for expressing the second bit in terms of A and B, as you said, but I wrote it as:

P(Answer correct) = P(A correct and B correct | (A correct and B correct) + (A wrong and B wrong) = 1)

smile) thus I counld not do anything with it !

Thanks so much mathsyperson smile You'rs kind !

popo

#4 Re: Help Me ! » Probability: 2 students and 1 professor » 2007-10-22 02:42:32

Hi, Thank you mathsyperson for giving this help. I presented your reasoning to my professor and he said "It seems to me that is correct" . So, many thanks.

But in the same time, he asked me to formalize this reasoning using "conditional probability". I am trying to do this but it's not trivial.

I think, it should be something like this :

P(the answer is correct) = P ( (A = right and B = right ) | knowing that they have done the same answer ).

So, how to formalize this condition?

Thanks smile

#5 Help Me ! » Probability: 2 students and 1 professor » 2007-10-22 00:24:00

popo
Replies: 4

Hi, someone please help me with this problem?

A professor ask a series of question to 2 students, A and B. If the students dont know the answer then they dont answer. If they think they have an answer then they answer.

For any question, A doesnt know if B can answer nor the answer of B (if B can answer). The same for B.

Before the test begins, the probability that an answer of A is good is unknown. The same thing for B.

Now, the test begins. Here is the score-sheet of the 2 students after many many questions:

For A: he has answered to 50 questions, with 40 good answers and 10 wrong. (80% good)
For B: he has answered to 75 questions, with 30 good answers and 45 wrong. ( 40%good)

By some calculus, the professor find that :
1/ The probability that the next answer of A is good is 0.8
2/ The probability that the next answer of B is good is 0.4
Suppose that (1) and (2) are correct.

Now, the professor ask the 2 students one more question. This time, both A and B think they can respond, and by CHANCE they give the same answer.

The question is: what is the probability that this answer, given by both A and B, is a good answer?

Uhmmmm....

I think this probability must line between 0.4 and 0.8 ; maybe (0.4+0.8)/2 = 0.6 ???

Thank you in advance smile

Popo

#6 Introductions » HELLO from a new member » 2007-10-21 23:56:31

popo
Replies: 3

Hi everybody, it's Popo I've just joined the forum, I'm in the IT field but I'm beginning to learn about Probability and Statistics . Hope to get some help from you smile .......

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