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can't edit my above post sorry i've registered now so that don't happen again. i realized i answered my above problem already. all i need to do is use the same formula i used for the 475 combinations just on a much larger scale and instead of it being 475 it would be the total number of rows which is a bit nuts but thems the breaks.
if anyone can offer another way or some further reading material that would be appreciated.
cheers.
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