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Hi,
Please produce both the principal and the square root signs. So I will know thew properly
So if I am grasping it now, the principal square of a number produces only positive number.
Therefore, the principal square root always infers a positive number.
Am I right?
Please confirm.
The fellow's post is at #38.
What is the subtle difference between, a square root and a principal square root?
Thanks.
Is a member trying to indicate that a number in a principal square root must have only one answer?
For instance, if 9 is in a principal square root, must it have only one answer 3?
If I am getting him wrong please correct.
Thanks.
How do you do Bobbym?
Okay.
I will return getting to nıght time.
Yes I tried to solve it once again and now I have the same answer as the first one, The root was my main problem, but now I have known how to go about that.
Thank you very much Bobbym.
God bless you!
Yes, Bobbym.
I just want to become used to them, cos in no time I will be teaching others.
Now, I had the same answer for the second question.
I owe you some thanks. :-)
0.36 * 10-12
= 0.6 * 10^-6
= 6.0 * 10^-7
It looks I was confused by the root.
= 0.36 *10^0
= 10^(-5-7)=10^-12.
Please can you provide the steps?
Thanks.
Right!
Yes. But all are in a square root.
Sorry! the denominator is 2.25 * 10^7
Forgive me.
1). I had 6.0 * 10^-15
And
2). I had, 6.0 * 10^-9.
Simplify the following, leaving your answer in standard form.
I have solved it but had different solution from what the book has, I need some assistance.
1) 0.81 * 10^-5/2.25 * 10
2). 0.0048 * 0.81 * 10^-7/ 0.027 * 0.04 * 10^6
Both number one and two are in a 'square root sign'
Please, I would be much obliged if you produce your steps here.
Thanks in advance.
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On what basis can time take a negative value?
I haven't heard that before, did he prove why?
Candidly speaking, since I started working on indices I haven't seen nor come accros a problem that could produce different bases as your own. As you made 9^(n+2) *3^(n+2) out of 27^(n+2)
Now I think the method that will be applicable to a problem is the one that must be used.
Thank very much Bobbym, God bless you.
Now I have learnt that! Thanks much Bobbym!
Okay, back to my question.
27^(n+2) =27^n * 27^2 = 3^(3n) * 3^(6)
.
Why didn't you use 3^(3n) * 3^(6) but rather wrote 9^(n+2) * 3^(n+2).
Thanks in advance.
27^n+2=27^n * 27^2
Thıs is how I mean, I will learn parenthesis in it proper way as you say.
For instance, 6^n+3=6^n * 6^3.
Because, for instance, 3^2 * 3^2=3^(2+2).
What do you say.
In fact I have not seen an indicial problem being split to get different numbers as the base. like what is in #269.
.Thiş problem is from indices.
I suppose the base must always be the same in each case. So I percieved it to be,
27^n+2=27^n*27^2=3^3n * 3^3+2.
I had thought should be so.
It's 27^n+2, and not 27^a.
Please, I double check it I have edited.
Thanks.
Hi;
How did you get,
9^n+2 * 3^n+2 out of 27^n+2?
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I have edited it.
Okay, Thanks bobbym.
Then I suppose, in change of subject, speed, velocity, time etc. Can't be negative in practise and therefore, if one is asked to make any of the above subject of a relation, should be in the postive form instead.