Math Is Fun Forum

1/1+3 - 3(x-1)/x^2-9.

That is it.

Thanks.

In the case of pythagoras theorem, I rarely see those sign in the final solution.

If for inştance, a student does that would not a teacher mark him down?

I was interrupted by some errand, boring one indeed.

Bobbym, it seems you mistakenly made a negative sign a positive sign.
The original is the same as the one Anomnystify solved please check the sign at #244. I mean;
3(x-1)/x-9,

Which you made it
3(x+1)/x^2-9.

Please could you demostrate to me?,  c'os I can't adentify it.

But if I am solving for U, and take root of both sides, I think there will come a root sign to the the R.H.S,  in front of the root sign there must be positive and negative sign present,  is that not it?

Thank you Bobbym.

So you mean there will be no square at the RHS at all? The book has it there.

My problem with it is, why there is no positive and negative sign in front of the root sign at the RHS in the book.

Yes that's fine.
But I suppose when  you solve  it down the RHS must take 'the square root sign'
and a positive and a negative sign as well. Strangely only the root sign is present.
What do you think is like that in the book?

This is a solved example from the book, but has no negative and positive sign in it finall answer though I expect;

Example 10.26

Make u the subject of the relation

V = 1/4(25-U^2)^1/2.

And

Make V the subject.

E = V + 1/2MV^2.

What do you make of this?
Why do suppose the book did not bring both signs at all, in each case?

Thanks.

Still I cant grasp why there is positive and negative sign before the root.

I have other questions but want this cleared.

Amen.

Is your interpretation the ones the book should have used?

2logy-log2x=log2(y-x)
express y in terms of x.

This how is in the book.

Thanks.