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25x3=75
Sin3a= 3sina - 4(sina^3) after simplification(don't know if I am correct) , then just solve the equation.but how to solve it? lol.
Find the sum of 1x2x3+2x3x4+3x4x5............
Find the formula for the sequence 2A(n-1) + An = 2^n
A(n-1) and An represent the sequence
x^4+4=x^4+(4x^2)+4-(4x^2) = (x^2+2)^2-(4x^2) = (x^2-2*x+2)*(x^2+2*x+2)
you can use 0=-x+x ,this kind of idea to do it
Yeah, I been reading books about number theory recently , but I am a newbie to it , still struggling with group theory . You can post it out , I'll try to comprehence it ,lol. P.S another question , how to apply imaginary number to prove certain problem , I mean how to consider using it?
divide both side by 4 , we have 3/4x+y=3 , then x must be in this form of integer , x=4n ,n can be 1,2,3,4,5....... , then the equation becomes 3n+y=3 , n and y can be anything thing ~infinte solution.
average speed v=s/t , s= bridge length+Train length (because it starts at one end of the bridge , when its tail pass over the other end ,we say it has gone through the bridge. so...
correct~
I am working on it , I tried when x=k ,y=k+1, no solution , x=k y=k+2 , no soltution , when x=k,y=k+3 one solution , then use induction on n , assume x=k , y=k+n , n>3 contains no solution. then if y=k+n+1 can be proved to contain no solution ,it's done , but I have difficulty in working on the last step.
Sorrri , my bad, The solutions must be integers , This kind of equations are called elliptic curves. Solve this can solve a problem which Fermat once challenged other two mathematicians , noted that 26 is between 25 , 27 , 25=5^2 , 27=3^3 , prove that 26 is the only number which lies between a square and a cube.
Prove that y^2=x^3 - 2 only has one solution.
Yah , I move with my family . I haven't got a computer yet .I am in a library.
Have any mathematician created a formula to determine the approximate value of n!
I was just wondering How many arrangements can be made to form a 9x9 grid Sudoku?
I realized that 16^2+15^2=481=13x37
Can't help asking :how to tell m^2+n^2 can be divided by x or y , when (m^2,n^2)=1 ,(m^2,x)=1
(n^2,x)=1 , (m^2,y)=1 ,(n^2,y)=1 . ?
Very interesting question!Pity that I can seldom be online now , but I have thought about it for hours , This is what I get :
15a + 16b =m^2 16a - 15b =n^2
a=14911 b=481 n=m=481
I don't know if it's right
after substitution of b , I get a=(15m^2+16n^2)/481
then I thought a can only be an integer when m^2=481^2=n^2 .so.....lol~
I have moved to California , I have just arrived , so many stuffs are not settled , see you guys soon.
Yep , but I assume a to be 1
lol , I see
And to how I get that , I get to find my notebook , it's been a long time .
OMg , Thank you for solving my mystery! I get this from a x^2+bx+c=0 equation , the determinant of root b^2-4c . I think I see now .hehe
Kewl , Jeg elsker Norge ! Norge er veldig gode! Jeg vi gjerne reise til Norge ! Og jeg kommer fra China.Mitt navn er Dalron.
Welcome! Welcome! Nice to meet you~ lol , I am so in love with Norway.
Who likes toast in milk?
Toast in milk actually pretty good, ,Clean toast will be quite dry I think
And Congrats ,Toast! , This is surely an awesome website~hehe
Hi I am Chinese. Nice meeting you!
Nice to meet you too, George!
Thanks , I want to enhance my skill from helping and asking questions ,hehe
Not sure