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Thank you
. Oh One last question. In this set: {(2,2),(1,3),(2,3),(3,3)} This isn't Reflexive because there's no (1,1)? Just double checking.
True. I am ready for it, but there are bits that are too complex. I'm going to do my best for it.
Yes I did. Just hope this doesn't pop up in the exam tomorrow. ![]()
Ohhh I see. This looks quick a long process to solve this problem.
OHH i get it.
hmm..I'm not too certain on line 3. :'(
Yea I get your example
Its bringing back memories.
Ohh i see.
Ohh right. So what happens to 1? Doe that get subtractedm or replaced by (y-1) ??
Ah ok. I was wondering does x count as 1 ?
Yes I get that. /you multiply both sides.
Okay. In 2/x, the x is just replaced by the (y-1) ??
Ohh. You replaced the x that was above 2/ , and input (y-1) instead ?? That the right way of doing it??
Ohhhhh! Silly me. From line 3 to 4, I got (y-1)/2, but your's the opposite round.![]()
Oh right! However, Why are you multiplying x, but not 2 ??
I didn't get what happens after y-1 = 2/x. Can you explain how you got x(y-1)=2 ??
Yes.. but it looks different ![]()
Hmmm you are right. I looked at the answer, an it says 'If f(x) = y, then 1+2/x = y and so x= 2/(y-1)'. I was wondering, where has the 2/(y-1) come from :S How did it get there??
Sorry to ask you again
But I have a small problem. It's a little off topic, but how would you answer this question...
The function f : A to B is given by f(x) = 1+ 2/x, where A denotes the set of
real numbers excluding 0 and B denotes the set of real numbers excluding 1.
Show that f is bijective and determine the inverse function.
I don't understand this question. Can anyone explain it to me?
Ohh. I guess most of it's common sense. I'll let you guys know if i get stuck on something in this topic.
I understand the methods and differences. But, when I look at the questions, I can't determine whether order matters or not ![]()
Ohhh I got it now. Going to do more practice on these! Thank you ![]()
Yep I got that. ![]()
Oh right i get that.