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A histogram charts occurences. One has 4 occurences as you see in the histogram. It is a peak not a valley.
ok and now about the valley ?
so you meant the minimum value would be our valley . is it ?
In your data set .. 1 is the most minimum value .
so it would be a valley . Is it ?
Hy Dear Bobby,
Is that correct way to get the location in x,y of mid point of width and height ?
please check it : http://i1069.photobucket.com/albums/u472/tina12354/recTest_zps8f233dc8.png
Thanks
Then Is there any way to find peaks and valley s?
Please guide me in this regard .
I have histogram shown in this figure : http://i1069.photobucket.com/albums/u472/tina12354/h1_zps40094c32.png
The problem is i need to detect peaks and valleys .
i tested 1st derivative . and where if difference tend to 0. there is a valley .
but for example if upper slope have value 26 , 26 . then it will also tend to 0. which will hard to tell that its valley or peak.
Any idea to get peak and valleys .
thanks
Hi;
Do you want the mid point of a side or of the rectangle?
yes , i mid point(int form of x ,y ) of a side of rectangle .
thanks
Hi;
To get the midpoint of a side you just add the coordinates and divide by 2. Same as for a line.
i know the way to get the mid point . mid point will be single value .
i want mid point location in x , y .
How can we get that ?
Well, we can find central location of a rectangle .
let say we have x,y initiail corner of rectangle is 1,1 . width and height of rectangle is 92 and 23 .
so cX = x + width/2 , cy =y+ height /2
that will give u central location of rectangle .
but how can we get location of mid point of width or height ?
i have a rectangle with height = 123 and width = 92. also i have central location x ,y = 47 , 62 .
I can find the mid point of width and height of rectangle .
but i want to get location x ,y of mid point of width or height of rectangle .How can i get that .
Can any one please tell me mathematically .
thanks
What is the physical meaning of mean value ?
using this formula .
mean = (f * m) / n
where f is the frequency of each class and m is the mid point of each class
n is sum of frequecy
What is the physical meaning of mean using above formula ?
Hi;
30% of ( 8 * 16 ) is 38.4. You need a rectanghle with an area of 38.4.
The width is 8 so we can only adjust the length from 0 to 16. We solve that with algebra.
L = 4.8
So the dimensions of the rectangle are 4.8 x 8. See the drawing.
k alright thanks
Try this one then.
you did not mention that how did u do that .
Hi;
You want the top block to be the small one?
yes
For the 8 x 16 rectangle you have in the picture. This is one answer.
hy .. bottom block is small .
second block should be 1st block.
I want 30% area should be for 1st block and the rest 70% area should be for 2nd block .
you did opposite .
and please let be know how did u do that .
thanks
Hi;
How do you want to split the big rectangle up? With one line or more than one line. Please look at the drawings.
like 1st figure. i meant by one line .
Hi tina123;
I have the same question. Percentage of what? Area? Points?
area ...
percentage of block1 area ,,
Hi;
Maximum percentage of what?
sorry .....
I meant to say , 1st block have minimum percentage as compare to 2nd block.
say block 1 have 30% and block2 is 70% .
Consider this problem : http://i1069.photobucket.com/albums/u472/tina12354/exam.png
I wanna divide a rectangle into two blocks where 1st block should have 30% of total block . any idea ..
How to do it ?
bin 0 , 1 , 2 , 3 , 4 , 5 , 6 , 7 ,8 , 9 , 10 ,11 , ...20 bins .
and frequencies are
255 , 70 , 60 , 50 ,10 , 5 ,4 , 4 , 60, 50 , 30 , 10 , 5 , 2, 2 , 1 , 0 , 5 , 3, 3
yes .. now i need probability yes ..
but these values
255 , 70 , 60 , 50 ,10 , 5 ,4 , 4 , 60, 50 , 30 , 10 , 5 , 2, 2 , 1 , 0 , 5 , 3, 3
are frequency of each bin ..
bobbym wrote:255 , 70 , 60 , 50 ,10 , 5 ,4 , 4 , 60, 50 , 30 , 10 , 5 , 2, 2 , 1 , 0 , 5 , 3, 3
Does this mean 255 zeroes, 70 ones, 60 twos etc?
Well that was a histogram that i supposed .
by considering a hill or mountain , i supposed that histogram .
that's it .
As i mentioned before. i can't ask any question related to my research.
i just need help in calculating things.
if you are interested in purpose then u can contact me rubi_faith@yahoo.com
then we could discuss issue and its solution. thanks .
255 , 70 , 60 , 50 ,10 , 5 ,4 , 4 , 60, 50 , 30 , 10 , 5 , 2, 2 , 1 , 0 , 5 , 3, 3
Does this mean 255 zeroes, 70 ones, 60 twos etc?
Well that was a histogram that i supposed .
by considering a hill or mountain , i supposed that histogram .
that's it .
HY .. but i do't need post #1 now .
Please look at current problem ./
thanksUntil you clear up post #1 I can not do the next part of the problem.
you already answered about area calculation..i have no doubt in that .
what do u wanna make clear ?
tina123 wrote:bobbym wrote:Hi tina123;
I do not know. But aren't we still working on the histogram?
yes we are still working on histogram .
Can we get energy from histogram ?
thanksDo you know how probability can compute from histogram ?
any one ? ?
HY .. but i do't need post #1 now .
Please look at current problem ./
thanks
bobbym wrote:Hi tina123;
I do not know. But aren't we still working on the histogram?
yes we are still working on histogram .
Can we get energy from histogram ?
thanks
Do you know how probability can compute from histogram ?
any one ? ?