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Yes, OK.
I would prefer
Bob
I don't know how to use LaTex. By the way, I don't have a computer or a laptop. Learning LaTex with a cell phone is a nightmare in terms of typing all the details carefully.
Again we have a rogue 6 in C.
Bob
Ok. I better pay close attention when typing my elements into the sets.
What do you mean by "rogue 6"?
Yes, that's ok. But you have typed
C = {1, 3, 4, 6}
That 6 cannot be an element as it's not in the universe. Fortunately it doesn't effect your answer.
Bob
Really? Why does 6 not effect my answer? That's a bit weird.
A set and its complement divide the 'universe' into two non overlapping sets with no elements left out of being in one or the other. So when you unite them you get everything, ie the universe.
And when you look to find what's in both a set and its complement you find nothing hence the empty set.
Normally when I'm showing union and intersection in a picture I draw two overlapping circles (inside a rectangle for the universe). But for a set and its complement a better picture is a rectangle for the universe divided by a single border making the two sets that don't overlap and together make the whole of the universe rectangle.
Bob
I didn't know this information. This reply makes good study notes. I think set theory is worth exploring in the near future.
Me too.
Bob
What a wonderful surprise. My textbook is not a set theory book. One day, I want to get deeper into this course.
Yes, that's got it!
Bob
Great news! I do my best to show math work.
Given x, x + 2, x + 4, x + 6, and x + 8, use the Roster Method to represent the given list of expressions.
Let E = set if expressions given.
E = {x, x + 2, x + 4, x + 6, x + 8}
Given 2/(x - 2) and (x - 2)/(x + 2), find the domain. Express domain in set-builder notation.
For 2/(x - 2):
x - 2 = 0
x = 2
D = {x | x cannot = 2}
For (x - 2)/(x + 2):
x + 2 = 0
x = -2
D = {x | x cannot = -2}
Let (B U C)^c = the complement of B union C.
U = {0, 1, 2, 3, 4, 5}
B = {2, 3, 4}
C = {1, 3, 4, 6}
B U C = {2, 3, 4} U {1, 3, 4, 6}
B U C = {1, 2, 3, 4, 6}
(B U C)^c = {0, 5}
I believe this to be right.
Given U = {0, 1, 2, 3, 4, 5}, B = {2, 3, 4}, and C = {1, 3, 4, 6}, find
B^c ∩ C^c.
B^c = {0, 1, 5}
C^c = {0, 2, 5}
B^c ∩ C^c = {0, 1, 5} ∩ {0, 2, 5}
B^c ∩ C^c = {0, 5}
I believe this to be true.
Definition of complement states:
If A is a set, then the complement of A, denoted A^c, is the set consisting of all the elements in the universal set that are not in set A.
It follows that from the definition of complement that A U A^c = U, where U is the universal set. It also follows that A ∩ A^c = null set or Empty set.
Why is this the case?
If A is a set, then the complement of A, denoted A^c, is the set consisting of all the elements in the universal set that are not in set A.
Let U = universal set
U = {a, b, c, d, e, f, g}
A = {e, f, g}
Find A^c.
Find A^c = {a, b, c, d}
I believe this to be right.
The first is correct for set builder notation. Your second answer is the roster answer.
Bob
That's exactly what I thought. I will post a few more basic set theory questions later on today.
Yes that's right. I've never heard it called the roster method though. Always good to learn something new.
Bob
Roster Method is the term used by Michael Sullivan in his College Algebra Edition 9 textbook. He is a famous mathematician and professor. I think he is retired by now.
I should find A U C first.
A U C = {0, 1, 2, 3, 4, 5} U {2, 4, 6, 8, 10}
A U C = {2, 4}
Yes you should but the union is {0,1,2,3,4,5,6,8,10}
Bob
Yes, my bad. A U C means set A union or united with set C. All the elements of set A united with all the elements of set C.
I then need to find find B intersected with A U C.
B ∩ (A U C) = {6, 7, 8, 9, 10} ∩ {0, 1, 2, 3, 4, 5, 6, 8, 10}
B ∩ (A U C) = {6, 8, 10}
I hope this is correct now.
It is correct.
Bob
Ok. I guess it was just pure luck at my end. The textbook begins with basic set theory. It is not a set theory book.
Yes, that's correct.
Bob
Oh, good. I had my doubts here.
A second way to denote a set is to use Set-builder Notation, where the set D of digits is written as D = { x | x is a digit}, is we are talking about digits.
We know the digits are single numbers 0 to 9.
Use set-builder notation to represent the set of even digits.
Let E = set of even digits.
E = {x | x is an even digit}
Is this correct?
How about E = {x | x is an even digit} = {2, 4, 6, 8}?
Which one is correct?
If we use the symbol D to denote the set of NYC boroughs, then we can write D = {Brookkyn, Queens, Manhattan, Bronx, Staten Island}. This method of denoting a set is called the Roster Method.
Use the Roster Method to denote the first 4 books in the New Testament.
Let N = the set of the first 4 books in the New Testament.
N = {Matthew, Mark, Luke, John}
I think this is correct.
Note:
B ∩ (A U C) means set B intersected with set A union with set C.
Set A = {0, 1, 2, 3, 4, 5}
Set B = {6, 7, 8, 9, 10}
Set C = {2, 4, 6, 8, 10}
Find B ∩ (A U C).
I should find A U C first.
A U C = {0, 1, 2, 3, 4, 5} U {2, 4, 6, 8, 10}
A U C = {2, 4}
B ∩ (A U C) = {6, 7, 8, 9, 10} ∩ {2, 4}
B ∩ (A U C) = null set or empty set
I think this is correct.
If A and B are sets, the intersection of A with B, denoted
A ∩ B, is the set consisting of elements that belong to both A and B.
Given set A = {w, x, y, z} and set B = {e, pi, x, y}
A ∩ B = {w, x, y, z} ∩ {e, pi, x, y}
A ∩ B = {x, y}
I think is correct.
The union of set A with set B, denoted A U B, is the set consisting of elements that belong to either set A or set B, or both.
Given set A = {red, blue, green, white}, and Set B = {red, white, orange, pink}, find A U B.
A U B = {red, blue, green, white} U {red, white, orange, pink}
A U B = {red, blue, green, white, orange, pink}
Is this done correctly?
Okay, i will do that.
I can help you with high school algebra.