Math Is Fun Forum

detail is here
above last relation simplifies to

which further simplifies to

this goes  to

which is quadratic equation in a^2
solving above one root is

if there is mistake sorry in advance.

hi JaneFairFax
i amnot understanding how we can conclude that .

Please can u give  me its reasons.

let O be the center of circle
join AC and OB let they meet at  E.
Now triangle ABO and triangle BCO are congruent. and it can be proved that AC and BO are perpendicular.
Now

area of triangle ABO can be calculated in two ways i.e

............1

.................2

equaling (1) and (2) and simplifing

which shows that d has the factors both not equal to 1 or zero.
hence d cant be prime.
  for minimum value i am trying

thanks for yours(both of you) great responses
one doubt is here.

both of you conclude that
c=2m and
3m+w=100
the second one suggest that possible value of m are 0,1,2....33
and both of u suggest that there are 34 solutions

i think it is not. because c=2m suggest that m is only even then possible value of m are 0, 2 , 4 , 6, ........32 then there are only 17 only solutions. am i right?

sorry in advance if any mistake.

can we say that if x^x = a^a, then x=a?i if then
above equation can be simplified to

x^x=1/16
and x^x = (1/4)^(1/4)
then we can say that x = 1/4

thanks mathsyperson
u r great

what if  we let    y    =   (x)^(x^1/2)-1/2=o and solve it graphically?

i think
(that the answer will be the intersection of x axis and the  curve line given by the new  equation.)

algebra section is good menu.
what if there are the menu(section) with different levels (categorized with different levels) so that all users with different levels can easily post their problems and view and reply the sections.

(sorry for posting suggestion on this post)

(i am not good in English. sorry)

if it is regular hexagon is posssible to prove. in that case all sides are equal and proof will easily follow.
if not the case then i think it is not possible.

sorry for inconvinience