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#26 Re: Help Me ! » integrals » 2014-05-21 19:43:06

Thanks for posting this up smile
Can you exaplin in a little more depth what this means?:

#27 Re: Help Me ! » Properties of Integrals » 2014-05-21 16:13:26

Ok, so I asked a tutor about this question today and was told not to bother with it (apparently an older version of the question sheet had been posted up & it was incomplete) neutral

This is the new one:

Is this statement valid?

I've worked a little on it before getting stuck at:

#28 Re: Help Me ! » Properties of Integrals » 2014-05-21 03:59:41

What do I do with h?
Do i make it du=hdx

#30 Re: Help Me ! » Properties of Integrals » 2014-05-21 02:47:07

As in this?

and then add in the limits?

#31 Re: Help Me ! » Properties of Integrals » 2014-05-21 02:21:54

Not really understanding what you mean by that

#32 Re: Help Me ! » Properties of Integrals » 2014-05-21 01:23:58

okay. So sub u=x-2, so it's h(u) and take 3 out to the front?
Where would I go from there?

#33 Help Me ! » Properties of Integrals » 2014-05-21 01:01:20

Shelled
Replies: 16

More integral questions...

So, I think I know what to do overall (apply the properties of integrals to the second expression and then sub in 5 for h(x) ) not too sure how to get there though.
Do I start off with this?

#35 Help Me ! » integrals » 2014-05-20 13:41:48

Shelled
Replies: 6

I've tried a number of equations for the above statement, and from the answers I get it seems like it's true?
If it is true, is there any theory that I can use to explain the statement?

#37 Re: Help Me ! » Derivatives. » 2014-04-15 12:34:28

I managed to simplify it to get the answer

#38 Re: Help Me ! » Derivatives. » 2014-04-15 12:19:23

Thankyou smile Got the right answer

#39 Re: Help Me ! » Derivatives. » 2014-04-15 11:46:01

So I used the product rule; then applied it all to the chain rule and got

i.imgur.com/McRIMWE.png

having trouble with simplifying it though

#40 Re: Help Me ! » Derivatives. » 2014-04-15 10:58:14

Okay, so not the complete answer, but am I going in the right direction?

and then apply the chain rule?

where 


   <--- not sure how to get the derivative of this. I think it's the product rule where...
                 
       and       

#41 Re: Help Me ! » Derivatives. » 2014-04-15 10:27:39

Actually, not the chain rule.
Would I use the quotient rule?

Edit: wait. I'll stick with the chain rule smile I think I might know how to solve this. I'll post the answer in a bit.

#42 Re: Help Me ! » Derivatives. » 2014-04-15 10:09:11

Okay, sorry it's been a long day. I just realized that the working out I put up was for a different question too hmm

#43 Re: Help Me ! » Derivatives. » 2014-04-15 10:00:47

Whoops, there's a typo in the question; it's supposed to be

Could I still use the chain rule?

#44 Re: Help Me ! » Derivatives. » 2014-04-15 05:08:34

Sorry, hopefully this is more clear (the question, with some of my working out)


i.imgur.com/VyT9EPC.jpg

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