You are not logged in.
It is obviously some sort of typo.
The book is before me now and has positive 1 just at the end.
Errr okay. So something like. (x^2 - x + x - x^0)
Hi;
This is exactly what is in the book then?
Yes Sir!. Positive 1 is at the end
I just wanted to be clear that the problem is:
If so then x = -1 and -2 are not solutions:
This is not zero.
Bob
Yes that's how it is arranged, in the book.
The order of operations goes
"Please Excuse My Dear Aunt Sally" or PEMDAS
It says parentheses first then exponentiation so
-x^0 says do the exponentiation ( raising to a power) first and then the minus sign. so it is -1.
Please I am not grasping what you mean.
Hasn't he raised a good point with
bob bundy wrote:I think it is unlikely that a book would use the symbol ^
I would agree, but you say it is there! But then his post #5 is correct and that is not a solution.
The book did not use the symbol ^, I rather used it , because the 2x +3 is at the top of the 3 in the book.
So, by combining them. x^2 - x + x - 1 = x^2-1. is this right Sir?
It seems that brought my mistake!
Errr okay, I understand it now, any number raising to the power zero is 1 therefore the 1 should take the sign of the x, Because is the x that makes the 1. I am right sir?
But sir, I think the negative sign is affecting the 'X' and not its power, please could you explain?
What does 3^2x+3 mean?
It means the 3 has raised to the power 2x+3.
Errr okay, I see it should be -x^ 0= 1. Is that correct?
Please, let me know I an wrong
X^0 = 1.
= -x^1
That is how it exist in the book I am working with.
I have solved a similar question successfuly, see.
3^2x+3 - 4(3^x+1) + 1=0
Yes, Sir.
I am ever ready!
I havent heard nor seen that before.
Here I go.
(3^x)^2 * 3 - 3^x*3^2 - 3^x*3 +1=0
Let 3^x = M. therefore substitution.
3m^2 - 9m - 3m + 1
= 3m^2 - 12m + 1=0
factorization seem impossible here.
There is no bracket involved in it from where I copied.
It is treated under indices.
I have solved similar problem but this seems insoluble at some point.
I will solvd for you to see where I got stuck.
I have solved the following, but it seems impossible to factorise at some point:
3^2x+1 - 3^x+2 - 3^x+1 = 0.
The book says, x=-1 or -2
It was impossible for to factorise at some point, let alone getting the answer.
I need assistance.
Thanks.