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#51 Re: Help Me ! » Algebra help! Inverse and composition functions » 2012-01-22 06:13:27

Yes. but wouldn't the +2 on the left hand-side be 2 + 4x  ??

#54 Re: Help Me ! » Algebra help! Inverse and composition functions » 2012-01-22 05:56:17

bobbym wrote:

Hi;

You need another variable. Are we talking about x = y - 2 / 4 ?

Yes yes. I forgot that:|

#55 Re: Help Me ! » Algebra help! Inverse and composition functions » 2012-01-22 05:44:55

bobbym wrote:

Hi;

I am not following you, what is y - 2/4 ?

Ohhh I forgot. I meant inversing y-2/4.

#56 Re: Help Me ! » Algebra help! Inverse and composition functions » 2012-01-22 05:41:26

bobbym wrote:

Hi

For g and g... I get (x+8)+8. In this situation, would you have to multiply both 8's or add them

You did the composition correctly, now you add the eights.

For the second question:

3x+ 2 is not the same as 3(x+2). 3(x+2) means multiply everything in the parentheses by 3. So you get:

3x + 3(2) = 3x + 6

Hmm... I see. Heres an example, y-2/4, I get 4(x+2), but the answer is 4x+2. faint Am I missing something?

#57 Re: Help Me ! » Algebra help! Inverse and composition functions » 2012-01-22 04:35:49

I'm back. Great news! I think I understand this! However, I have a few problems that I want to clear up on. In the composition functions, Say you have f(x) = 2x    and    g(x) = x+8.

For g and g... I get (x+8)+8. In this situation, would you have to multiply both 8's or add them?

Also, for inverse function. Is 3x+2 the same as 3(x+2) ???

#58 Re: Help Me ! » Algebra help! Inverse and composition functions » 2012-01-18 03:31:01

bobbym wrote:

Can you do another one?

I will do another for myself and see how I will go. I have to study for another module. So, for now, you can relax smile

#60 Re: Help Me ! » Algebra help! Inverse and composition functions » 2012-01-18 02:48:06

bobbym wrote:

Now use some algebra to clean that up a little.

f(x+1) = x+1 + 4

Simplifying often just means combining things together. Well the 1 + 4 is 5 so that means we can simplify that to.

f(x+1) = x+5

We are done!

Ahh I get it now! YESS!:)

#61 Re: Help Me ! » Algebra help! Inverse and composition functions » 2012-01-18 02:38:51

bobbym wrote:

HI;

f(g(x)) = g(x) + 4

Now we replace that g(x) with x + 1 because g(x) = x + 1.

f(x+1) = x+1 + 4

See how each g(x) was replaced by a x+1?

Yes. the x from f(x) is replaced with the equation of g(x)!

#62 Re: Help Me ! » Algebra help! Inverse and composition functions » 2012-01-18 02:33:58

bobbym wrote:

Hi;

Hold it, watch what I am doing.

f(g(x)) = g(x) + 4

See the boldfaced g(x) in the above equation?

OOh yeaah. I forgot to put that on. oops.

#63 Re: Help Me ! » Algebra help! Inverse and composition functions » 2012-01-18 02:29:38

Okay. f(x) = g(x) + 4 ?  Or is it the wrong way round?

#64 Re: Help Me ! » Algebra help! Inverse and composition functions » 2012-01-18 02:18:45

bobbym wrote:

Hi;

You skipped a step.

f(x) = x + 4

Now putting a g(x) wherever we have a x in f(x) we get:

f(g(x)) = g(x) + 4

Ohhh I get that. In that step you just plot g(x) in x from f(x).

#65 Re: Help Me ! » Algebra help! Inverse and composition functions » 2012-01-18 02:13:07

bobbym wrote:

Hi;

Not quite. But do not get discouraged you will soon do it like a champion.

See the x in the equation

f(x) = x + 4? I want you to put a g(x) wherever you see one.

Hmmm. Putting g(x) will result in x(x+1)+4 ?

#66 Re: Help Me ! » Algebra help! Inverse and composition functions » 2012-01-18 02:02:22

bobbym wrote:

Okay, I will put another one down and you do it for me:

What is?

(x^2+1)+4 ??

#67 Re: Help Me ! » Algebra help! Inverse and composition functions » 2012-01-18 01:55:53

bobbym wrote:

Hi;

Not exactly, all we are doing is substituting. Then we have some algebra to clean it up.

Let's do another one:

Wherever the is an x , we substitue g(x) for it and g(x) = 2x.

Ohhh okay. I think I get that. I was wondering why do we need the brackets?

#68 Re: Help Me ! » Algebra help! Inverse and composition functions » 2012-01-18 01:45:55

bobbym wrote:

Hi;

f(x)=2x+3

g(x) = x+3

This just means:

So for every x in f(x) we substitue a g(x)

Follow up to here?

I think I get it. When there is x in f(x) and g(x), it can't be turned into x^2.

#69 Re: Help Me ! » Algebra help! Inverse and composition functions » 2012-01-18 01:29:27

bobbym wrote:

Hi;

I meant in particular.

Like getting putting g into f and f into g. I get mixed up on which way to input correctly.

#70 Re: Help Me ! » Algebra help! Inverse and composition functions » 2012-01-18 01:22:42

bobbym wrote:

Okay, what problems are you working on, I forgot.

The composition of functions.

#71 Re: Help Me ! » Algebra help! Inverse and composition functions » 2012-01-18 01:19:24

bobbym wrote:

Hi BlitzBall;

Well rested and ready to go!

Hi, I'm ready to go smile

#72 Re: Help Me ! » Algebra help! Inverse and composition functions » 2012-01-17 12:01:30

bobbym wrote:

Hi;

You would first minus 6 from both sides and then divide by 4 to both sides.

It is time to sleep for a couple of hours, I am really tired. I will see you later and help with the compositions if no one else has

Oh right I will give it a try. Thank you, Bob. Good Nightsleep

#73 Re: Help Me ! » Algebra help! Inverse and composition functions » 2012-01-17 11:57:34

bobbym wrote:

One more step:

And we are done!

Ahhh I get it. Last quick question, what if it was 4x + 6? Wouldn't that be the same method as you showed me?? Just explain it. I don't want to waste a lot of your time.

#74 Re: Help Me ! » Algebra help! Inverse and composition functions » 2012-01-17 11:48:31

bobbym wrote:

x/ 4 is the same as x * ( 1 / 4 ). The fours cancel in either case and just leave the x.

Now we swap the x to the other side.

Ohh I see. Surely, that is the answer??

#75 Re: Help Me ! » Algebra help! Inverse and composition functions » 2012-01-17 11:41:11

bobbym wrote:

No, it would be one, because 4 * ( 1 / 4 ) = 1. So let's clean up this last step.

Okay. So, doing *4 on the right-side leaves x on its own, and the fraction is removed? where is 1/4 coming from?

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