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Yes.
What is a Klein Absolute Invariate?
What is an algebraic integer?
What is a class number?
And what is the prerequisite knowledge to this.
No, you don't have to explicitly solve for m. I just added that, because I thought that solving for m would help find the actual constraint.
Like, you can't simply say
"The equation is satisfied when
"Because.... well... that's obvious... right?
I'm just looking for simpler cases when both sides are equal.
I need help breaking down this theorem.
Yes, m,n,s,t ≠ 0. And you cannot just restate the problem.
Thanks! That helped a lot.
How did you see that?
I have the following equation
Please no trivial answers please.
In need help with solving
How do I evaluate this? (Note that I mostly need help with the actual algebra part)
And unfortunately, it only works with Heegner numbers.
Implying one cannot evaluate
Complicated logic? I don't understand.
Another way, is to notice that the coefficients go in a,b,a.
Dividing both sides by x, we arrive at
Wait, what do you mean by "what happens next"?
I'm just as stumped. I don't know why the formula works and how it works. I just know that it works.
Um... compound interest vs. simple interest..?
Actually, I now think the problem is a bit "redundant"..?
Wikipedia describes a simple procedure. And I know what to do, but I don't understand why that method works and why they got the steps. Unfortunately, it only works on Heegner numbers. (Implying that you can't evaluate with it)The concept is simple.
@bobbym What's plsq?
@zetafunc I understand the part where you said Taylor series expansion, brilliant that is! But how would you calculate the infinite sums?
Given
Sure.. determinant...
Why is division by a matrix not defined? Isn't a matrix simply subtracting values, given the fact that the elements of the matrix can never all equal 0...
Note that Ramanujan found this a long time before computers. Thus, he had to have a method for calculating these transcendental numbers!
Actually, this isn't Ramanujan's method. But doing an extensive amount of internet searching, you can find theorems such as these.
I have found the solutions as
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Lots of internet searching...
Focusing on Ramanujan's method for solving these types of equations might also be a big factor.
Yes. I realized that.
It turns out, that the number of cosines are m where 6m+1=p where p is the roof of unity. So for my example, the pth root of unity was 31. Thus, m=5 and we have
Yes. I have figured it out. We have
See if you can algebraically prove