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You have a series
I read it on the book, says, if you find the expression for partial sum for the series then take the limit, if it be the sum of the series
And I also know rearranging terms is not valid method of dealing with series
but what if I rearrange the term to get the expression for partial sum, and then take the limit, it sounds valid, but I am not sure
like rearranging that to
Oh, my bad
so its there's a relationship e(p) , whenever |x-2|< p , | x^2+x-6/x-2 - 5| <e
| x^2+x-6/x-2 - 5| = | (x-2)^2/(x-2)| =|x-2|<e
Then e=p
you have two choices ,
1. factor it as x^2+x-6=(x+3)(x-2) , then it would be x+3 =5
2. apply L'hosp...(spelling XD) rule, take derivative 2x+1=5
First time on this stuff, and I need an example on how to apply Jacobian transformation
I tried to substitute x as
, y as and rewrite the equation as Z(x,y) and integrate itHere's my work
sorry for the late reply, I suppose it should be
ah, I see, its trivial now, thx~
I tried to expand it, but doesnt seem to work, I tried udv=uv- vdu one as well.
its my bad for not explaining it clearly
By vector, or function kinda of method (Jane mentioned)
I could work it out
I just wanna make sure, the 3rd method is valid, (I dont see any flaw)
Thanks~
I know this can be done by drawing out vectors, but I'd like to know if my work is valid , Thanks in advance
Two balls A, B connected with a rigid stick L in length. A is moving at a constant speed V ,when the angle is 60, what's the speed of B?
I'll do the first one
If A+B< 10 , the solutions is A+B=C (1,2,3) (1,3,4), so on..............
If A+B>or = 10 , AAA+BBB would be 4 digits, so it wont work
In mathsy's case
Can I prove it like this
Consider, a, b two vectors
|a+b| is the length of the 3rd side of triangle consisted of a and b
|a| ,|b| are length of side a and side b
sum of two sides always larger than the other one
and when the two vectors are parallel they equal
Wait,
For the second one,
x = DBtan54
x = [(350tan32)/(tan54 + tan32)]tan54
x = 138.043885kmx = [ (350tan32) / (tan54 + tan32) ] tan54 = 150.416
My calculator does not yield the 138.04 value.
Check your batteriesIncidental question:
For a really precise answer, what is the elevation of the points A and B?
When you say "above the ground" are you referring to see level, actual ground, or the earth gravity model? In any case what is the Latitude/Longitude of the observation points? Does Refraction need to be accounted for?Just an observation:
point A is approx. 4.5 km above "ground" and point B is approx. 1 km above.assuming they are earth based.
Wow, I guess you dont need to consider it as a Spherical triangle, that's a lot of trouble lol
actually, if you know that DB+AD=350 , you could change it to AD=x/tan32 , DB=x/tan54
AD+DB = x( 1/tan32+1/tan54)=350 , your work looks fine, I think there might be some minor error
username, I think u already worked it out
Since she asked for more clue which means that two possible answer add up to the same sum
Then he told her that he had an eldest son
Which eliminated the other answer
The vol of nitric acid at the beginning is 200x0.5%=1
The rate of flow in nitric acid is constant 6x20%=6/5
The escaping rate of nitric acid should be v=8x(temp density of nitric acid) = 8x (amount of acid)/(total volume)
The speed of the change of volume of Nitric acid
Total volume = 200-2t
To question 2:
Density = V/(total volume)
In my opinion
How do I put Double integration over a region D, the code \iint doesn't seem to work?
The region should be the upper half of the rectangle divided by the line y=x, right? then I still think it should be 0 to y with respect to x
6. was he born in Asia (from middle east to Japan)?
Can't be right as there is no 4 used - I thought e.g. E had to keep its value in each line of the equation...
It was my mistke, N,O take the value of 6,4 , I put it wrong, , just a minor mistake