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Haha Thanks Jane
Don't worry, I get it. It forget it helps to actually write things down when doing maths.
Evaluate for all real x:
The solution I have is:
Replacing x by
and dividing both sides by and summing to n gives (before taking the limit as n tends to infinity):Could someone please explain this last step?
Thanks
JaneFairfax wrote:Treating the LHS as a quadratic in
, we see that its discrimant cannot be positive.I don't follow this part. Why can't the discriminant be positive?
The fact that the quadratic is always greater than or equal to 0 means that it must have at most one real root.
EDIT: In other words, what Jane said. I clicked 'quote' and left the room for too long
I've seen a nice combinatorial 'proof' that 0^0 = 1.
"The cardinal number n^m is the size of the set of functions from a set of size m into a set of size n. If m is positive and n is zero, then there are no such functions, because there are no elements in the latter set to map those of the former set into. Thus 0^m = 0 when m is positive. However, if both sets are empty (have size 0), then there is exactly one such function the empty function."
The only function between the empty set and itself is the identity function.
What's the black square for Jane?
That's really nice
Alternatively,
But Jane's method is nicer.
I've spotted it. Missed the 5 out when I replaced x's with t's.
Sometimes it helps just to see it written clearly
Can someone please tell me where I've gone wrong?
Thanks.
Thanks guys and girls
a/(aa+4) ?
Sorry?
Having just evaluated 45 integrals, my brain has gone numb.
Can someone please tell me what to do for this:
Thanks.
I'd like to add: this really is very good.
A very well put argument against the way maths is taught in schools:
Offer came from Bristol today
No idea what to put as my insurance.
Oh, well if it is good luck with integrating it.
I think it's more likely to be x sec^x tanx. If so, use integration by parts (differentiate x, integrate the rest)
You have something of the form
. Does that help?i still need to learn all that....mind explaining?
Look at the series expansions of e^x, and let x = iθ (simplify a bit)
Compare this to the series expansions of cosx and sinx. You should be able to see why e^iθ = cosθ + isinθ.
By exponential form, Kurre means use the relationship:
Easy mistake to make. You'll stop making it (as much) as you continue to do more maths (mainly because you work in radians pretty much the whole time).
No problem
We have that
I'm not sure, but can you not just say that because all the coefficients are real,
?Which means
, and so if z is a root then so is z_c.Yes, that's right
There are 36 ways of choosing a pair of vertical lines, and 36 ways of choosing a pair of horizontal lines. Each pair of vertical lines can be matched with each pair of horizontal lines: the first pair of vertical lines can match with 36 pairs of horizontal lines, the second pair of vertical lines can match with 36 pairs of horizontal lines... the 36th pair of vertical lines can match with 36 pairs of horizontal lines, which gives a total of 36*36 matchings.
Consider the vertical/horizontal lines that separate the colums/rows. There are 9 vertical lines and 9 horizontal lines. In order to form a rectangle, you need to choose 2 vertical lines and 2 horizontal lines. How many ways are there of choosing 2 lines from 9? How can you therefore find the number of unique rectangles?