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#827 This is Cool » Pale Blue Dot » 2007-09-01 02:04:50

Identity
Replies: 1

This is a fantastic narration taken from physicist Carl Sagan's book 'Pale Blue Dot'. Carl was a great man who inspired the world, and if you haven't seen his TV series 'Cosmos', that is something I would highly recommend. R.I.P Carl.

http://www.youtube.com/watch?v=p86BPM1GV8M

#829 Re: Dark Discussions at Cafe Infinity » ! » 2007-08-31 16:24:33

It really depends how much time you have to do it. If you have a heap of other pressing subjects then it would be bad for you but so long as you have the time I see no reason why you wouldn't do it. After all, as Ricky said, it's all about experience

#830 Re: Dark Discussions at Cafe Infinity » Quantum Physics » 2007-08-31 04:34:39

I had to write an essay on the same topic a few days ago as well. I think some really good references are 'A Brief History of Time', especially the illustrated version and of course Feynman's Lectures.

#831 Re: This is Cool » Cool trick » 2007-08-30 03:37:06

Well, unless we assume either a or b are integers we will get an infinite number of solutions. If we assume one to be an integer, we can work upwards starting from the smallest values of a.

#832 This is Cool » Cool trick » 2007-08-30 03:14:21

Identity
Replies: 4

This is a little trick I have found incredibly useful (especially in a past competition). The explanation is messy and bad, so please forgive me, I'm a noob at number theory too, so this is new for me. I'd be happy if someone could help clean up the explanation big_smile

If you have an equation of the form

With variables x,y and constants a,b,c,

It can be turned into the form:

Now introduce a new variable d such that



I find this very important as it allows you to be able to work out the possible numbers rather easily. The only real 'trick' which separates this from normal factorisation is the introduction of the new variable which is in ratio.

E.g Find all non-hypotenuse side lengths a,b of a right triangle, such that the hypotenuse of that triangle is equal to its area.








Now you can systematically work out the possible values of a and b. In this case they might not be rational but you get the idea. dizzy

#833 Re: This is Cool » Domestos Kills Germs! » 2007-08-29 20:06:38

Anthony.R.Brown wrote:

.001% In the Germ world is Massive!...........

So is 99.999% ? rolleyes

#834 Re: Help Me ! » How come?? » 2007-08-29 20:02:21

I'll assume population decrease is compounded, the formula for which is as a follows:

Here we have



#835 Re: Help Me ! » Simplify expression Math » 2007-08-24 21:07:08

I see, I had made the mistake of:

#837 Re: Maths Is Fun - Suggestions and Comments » Small text after Latex » 2007-08-24 10:39:43

btw,How can I get to upload my own image to upload? I clicked on the scroll-down option in My Profile but all it does is delete the style sheet???

#838 Re: Maths Is Fun - Suggestions and Comments » Small text after Latex » 2007-08-24 10:37:42

I've tried the other styles, I still can't see it

#840 Re: Jokes » Good jokes, aren't they? » 2007-08-23 00:41:33

Hahaha! Bad move by the atheist.

#841 Re: Jai Ganesh's Puzzles » 10 second questions » 2007-08-23 00:35:21

ganesh wrote:

190. What would be the last digit of
43^133?

191. What would be the last digit of 47^51?

#843 Help Me ! » Help me with this triangle! » 2007-08-21 23:57:27

Identity
Replies: 4

I have a triangle HPN with two side lengths HP = 54km and HN = 75km and included angle 15 degrees. Let the angles opposite HP and HN be

and
  respectively. By use of the cosine rule I get

Next, I use the sine rule to solve for remaining angles:

The last angle I will find using the sine rule again.

Ok cool, this triangle has 92.915 degrees, I think I'm going mad...

#844 Help Me ! » Deriving Law of Cosines » 2007-08-20 23:56:09

Identity
Replies: 0

Given

[previously proven], use corresponding results to prove the cosine rule.

Thanks

#845 Re: Help Me ! » Oh no, I've got like 273 viruses! » 2007-08-20 18:28:12

mikau wrote:

well i downloaded AVG free and it managed to find and delete 11 viruses, but it doesn't check for spyware.

I downloaded SpyBot as Identity suggested, it ran a scan and detected over 2,000 parasites, but once again it informed me after the scan that i had to purchase the full product in order to remove them.

So does anyone know of any free anit spyware services?

That's odd! My one fixes the bugs, perhaps I downloaded one of its older versions or something...

#846 Help Me ! » Deriving the Sine Rule » 2007-08-20 06:11:40

Identity
Replies: 1

Write down two formulae for the area of Triangle ABC with sides a, b, and c, and deduce the sine rule from these two.

I'm assuming here the question is refering to the sine formulae for area and heron's formula, but it's really hard to derive because things get messy quickly with the heron's formula! Is there any simpler way to do things?

[don't mind with this question, a moderator can delete this post]

#847 Re: Help Me ! » Oh no, I've got like 273 viruses! » 2007-08-20 06:09:16

It's possible to have that much adware/spyware, but not viruses, it just makes your computer real slow and u get spam.

#848 Re: Introductions » Homeschooler » 2007-08-20 02:26:09

Yeah my school signed us up for mathletics in year 9, and it was awesome, racing against people from all over the world in basic operations. It's a great website for kids in lower year levels, and the subscription cost really isn't that significant.

However it should also be noted that there are other great places to learn these things, Mathsisfun has Reaction Math, and I found this Other cool arithmetic site. big_smile

#849 Re: Help Me ! » Further Trig: Bearings Question » 2007-08-20 01:46:55

We know that


(alternate angles)

Also,


(alternate angles)
(complementary angles)

Hence,


Next, letting we express x and y in terms of the height:




Now since we have LA and LB, and we know ALB is right angled, we simply use pythagoras to solve for h:

The answer is 80.88m. (The answers are wrong)

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