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Thanks, Bob. How does this look?
Let y be the distance the sled travels.
When y(0) = 0,
And so after 1 second in time, the sled as traveled 1.31 meters and with a velocity of 4.473 m/sec.
How does my math look?
Oops... almost forgot about this problem. I get that that limiting velocity is 6m/sec. Did anyone else work this problem out?
Hello. I have been working various problems and I think I am doing alright. I am not sure what to do with this one, however.
"A sailboat is running along a straight course and under a light wind at 1 m/sec. The wind wuddenly picks up, applying a constant force of 600 N onto the boat. The only other force that is acting on the boat is water resistance where k=100 N-sec/m that is proportional to the velocity of the boat. The mass of the boat is 50 kilograms. First find an equation for the motion of the sailboat, then determine its limiting velocity under these wind conditions."
Here is what I have so far: Ft is the total force on the boat, Fw is the force of the wind, Fr is the resistance on the boat by the water, k is the proportionality of the water resistance, m is the mass of the boat, v(t) is the velocity of the boat.
Looking it up, I find that acceleration is the force divided by the mass (right?) so...
How does that look so far? Am I heading in the right direction? What does N-sec/m mean, anyway?
Thanks bob. Sorry to not respond right away, I've been distracted. I appreciate your help. Setting these things up is the hard part, for me.
I have a few other word problems but I am going to work on them myself, first.
Whoa... thanks for the full reply.
Let me read what all you said.
First of all, the initial differential equation was given in the problem. Does it help to change it to the form you put it in?
"Assuming the flow of water (its volume per unit of time) through a hole in the bottom of a tank is proportional to the product of the area of the hole and the square root of the depth of the water. Let
where h(ft) = depth of water, A(ftxft) is the area of the water's surface at time t in seconds, and B(ftxft) is the area of the hole. The constant of proportionality k depends on the condition.
a. Find the time required to empty a cubical tank whose edge is 4 feet long. The tank has a hole 2 inches in diameter in the bottom and is initially full. In this case, let k = 4.8.
b. A funnel with the shape of a right circular cone and with vertex down and is full of water. If half the volume of water runs out in time t, how long to completely empty?"
Q1c OK so far.
What more is supposed to be done with this sort of problem? I am not sure how to solve for a second order differential equation. That is also what I am kind of wondering about #4.
Problem 3:
Equilibrium points at
and
Problem 5 worked out:
a. Derive the general solution.
How about that one? There may still be a mistake somewhere, I dunno.
#2....
a. Equilibrium points at x = y = 1
b. See attached documents.
c. I am not sure how to plot an individual plane?
Me again. Solving problem 1,
Answer:
b.
Answer:
c.
Answer:
For problem 5
Solving the second equation yields
Plugging this into the first equation gives
Solving this for x(t)...
For problem 6, let
and
For problem number 7 I am required to use a program written in class and executed in Maple. I get that y(1), when t equals 1, is 1.342224239.
Hello.
I am practicing a variety of general problems and I was hoping I could get my solutions verified so I can see whether I am understanding the concepts or not. I am putting them all into this one post so not to flood the forum with individual posts. My solutions will be in the posts following.
Thanks in advance. ![]()
1. Solve the following:
b.
c.
2. Plot the phase portrait of the system and answer a - c.
a. What are the equilibrium points of the system?
b. What is the long term behavior of the system with initial conditions x(0) = 3 and y(0) = 1?
c. Plot the x(t) and y(t) planes.
3. Find the equilibrium points:
4. Plot the phase portrait and do a - c.
a. Determine the long term behavior of the system.
b. Plot y(t).
c. Solve the differential equation.
5. Consider the partially decoupled system:
a. Derive the general solution.
b. Find the solution that satisfies the initial condition (x0,y0) = (-1,3)
6. Solve the differential equation:
7. Use Euler's Method for Systems to find y(1) given x(0) = 0, y(0) = 2, with a step size of .1 for the system
I'll be working these out throughout today and tomorrow. Thanks again!
Thanks. ![]()
"Newton's Second Law, F=m*a, may be viewed as W = m*g where W is the weight in pounds and g is gravity. A sled weighing 100 lbs is being pushed in a straight line against the wind by a force of 10 lbs. Friction is negligible but there is an air resistance whose magnitude in pounds is equal to twice the velocity of the sled in feet per second.
"If the sled starts from rest, find the velocity and the distance traveled at the end of one second."
These physics-type questions throw me off. I have never had physics. We know the sled weighs 100 pounds and it's being pushed by 10 pounds of force on the horizontal... and we know that the wind has a magnitude of twice the velocity of the sled.
How is a problem such as this started? Does one find a position function and then differentiate? What is the difference between mass and weight? How should this solution be started?
Thanks for the help.
Find the abscissa of the point where the curve
intersects the curve represented by the particular solution of
where x = e and y =1.
The particular solution I came up with was
This intersects with the graph of e to the x at
Am I correct? I am not sure what I am doing or if it is right.
No way, man. You did a great job. I really appreciate all of your effort. This is a great place to come get help with textbook problems.
Thanks so much for your help.
Hey bob,
I saw your replies earlier and wasn't sure what to say so I went and asked my instructor about these types of problems. What he said is something along these lines:
In an ecosystem we care about the evolutions of the two species in question as the species interact with one another and in any predator-prey interaction, the predators will benefit while the prey will not. The two systems, given above, give two different scenarios. By looking and what each derivative concerns itself with and how the derivative will change with respect to the other variable, one may deduce which variable is which and then to the size of the predators as well as the prey.
For example, in the first system,
we can see that x with respect to time is going to be harmed greatly by an increase in xy interactions (the -20xy represents x and y interactions) because it is negative. The key here is looking to the portion of the derivative that has to do with both terms x and y. Therefore, the more that x and y interact the more it hurts x and x is therefore the prey because whenever a predator and its prey interact, within this scenario, we can assume that the predator will eat the prey.
Likewise, y is therefore going to be the predator which can be seen by the positive xy/20 where every time the two interact the predator population increases. We can also tell by this system that the prey must be very small for when they increase in number the predators benefit only by factors of 1/20 while, for the prey, the increase of predators affects them by a factor of 20 and so the predators must be large animals, such as wolves and field mice or something.
As for the second system,
It is now obvious that the predators must still be y for as y increases it hurts the change in x more and more. However, now the interaction of the two in the derivative of x is divided by 100 and so the predators must be very small in this system. In the prey system, dy/dt, the factor of 25 benefits the predator population. Ergo, the predators must be very small and the prey very large.
You may furthermore see, too, that if the predators were to go extinct, the prey would approach a carrying capacity of 15 units. The same can be said for if the prey go extinct, the predators will then diminish in count until their number is zero.
I am trying to understand how to 'read" a set of equations and it isn't really making sense. Here is an example of the sort of problem I am trying to learn about:
"In one of these systems, the prey are animals very large in size and the predators are very small animals. Thus it takes many predators to eat one prey, but each prey eaten is a tremendous benefit for the predator population. The other system has very large predators and very small prey. Determine which system is which and provide a justification for your answer."
Systems:
and
Apparently we are not only concerned with the evolution of the predators and the prey within some habitat but somehow it is supposed to depend on the size of the two? The book gives elephants and mosquitoes as an example of large and small predators and prey... but the idea of elephants eating mosquitoes is silly. That, however, is the objective.
How is this determined?
Yep.
Also, if you are going to take that exam you may want to make reference to a table of differentiation rules such as this one:

Found here: http://mpec.sc.mahidol.ac.th/radok/physmath/mat12/fig227.jpg
Have fun. ![]()
I happened upon this quiz which I thought might be helpful to the differential calculus student.
http://archives.math.utk.edu/visual.calculus/2/formulas.2/index.html
It is multiple choice so if you get stuck on a problem you can just guess. And in case you had to guess you are shown the solution for finding the answer so that you can learn about calculus as you go rather than simply skipping to the next question.
Furthermore, the questions seem to be in a random order which makes the practice quiz ideal for doing again and again.
![]()
I assume my solution is confirmed correct then.
Thanks for your help. ![]()