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Now, I'm curious...
what is the difference, really...
novice, member, full member, moderator, administrator
How is it that I became a member? How did I get past novice? Why am I not a full member?
It looks right to me!
And, it is definitely a minimum...the value of the derivative function around x=2000 confirms it...plus the second derivative [ 1600/(x^3) ]at x=2000 is positive...
I can't remember...but isn't it usually the place where the derivative is equal to zero...those critical points are either maximums or minimums, and so I suppose that would be a place to start.....??
good luck
It sounds like there were a lot of people from the UK...
I'm a Chicagoan
oh my...you are absolutely right...I over-simplified the problem...whoops!
That's why you're the moderator and I'm just a member...;)
LOL..
It is way to early for me to be laughing that hard...
I am going to learn how to say cotton in every language...that is a great idea...
also, that joke is absolutely freakin hilarious...right up my alley
???
I don't think the 12 is the hypotenuse....
The right angle is formed at the origin by the x and y-axes, isn't it?
Hello all!
Obviously, I am new to this forum...I am interested in hearing any great ideas for teaching mathematics to secondary school students. Also, I myself am interested in real analysis, abstract geometry, and logic...also love riddles, puzzles, and terrible jokes...
Q: What did the zero say to the eight?
A: Nice Belt!
I like to think about...
which is greater?...
the infinite number of real numbers between 1 and 2, or
the infinite number of positive integers?
can we really make a distinction between countably and uncountably infinite sets?
I think you had a diet soda...there is something about the sugar in the regular sodas that would keep it from freezing as fast. (maybe the other way around, but I think I'm right)
Linoleum
"SERENITY NOW!"
I'm having trouble visualizing what you mean...we are talking about a concave quadrangle, right?...Then P is outside of the qdrngle?
I'll keep at it and get back to you, but any sort of clarification so that I could make a picture in my head would help.
Else, if you have since solved this, I would love to see your proof.
I think that's the only one...since one square face is given, that accounts for four vertices...then there is only one other to work with, so you need a pyramid.
1) I am not certain I am understanding this problem correctly, but here goes...
The graph of the equation x^2+y^2=4 is a circled centered at the origin, of radius 2.
A line drawn from the point (12,0) that is tangent to the circle would intersect the circle at one of the y intercepts.
By drawing this line, we create a right triangle, with a base of length 12 on the x-axis, and a height of 2 on the y-axis.
You can now plug these into the pythgorean formula, yielding the square root of 148
2) If we let x be the number of pencils Bob had to start with...
the number of pencils he had AFTER he gave some to Barbara is given: x-(4/5)x or equivalently, (1/5)x...
then, after he gives some pencils to bonnie, he has:
(1/5)x-(2/3)(1/5)x or (1/15)x
Now this last term is the number of pencils left after he has seen both Barbara and Bonnie, and we know from the problem that this number is ten...hence
(1/15)x=10 and x=150 (the # of pencils he had to start)
3) sorry...I don't know what hamburger style means