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90.22 in the add single. That should be hard to break I guess. Took me like 10 tries.
Ok done. First in all. Im gonna wait till someone beats me on one and then focus on that one etc.
I have no life ![]()
Nevermind, I broke my record of 86 and now I got 89 and its there.
Im going for first place in all ![]()
Why doesnt my highscore (and therefore 1st place) of the add single, show in "my" page.
http://www.mathopolis.com/user.php?u=luisrodg
Already set a highscore of the first counting game ![]()
Since theres a theorem that says:
Let:
To show f is one-to-one:
Assume:
and we need to show that:
So we get:
How do we go from here?
From the limits of integration you need to get the domain of integration and then from that domain setup a new double integral but with the other order.
Thanks for all the comments!
I also think pictures are good. Like you said, its nice to know the face behind the words. Waiting for yours!
Regarding the car, it gets me lots of speeding tickets and cops in Miami hate me
hehe (or is it me who hates them?
)
I've been a member of this site for more than a year I think and I really hate chatting with people and not knowing how they look. So here my goes my introduction again, this time with pictures:
My name is Luis Rodriguez and I'm 19. I go to university in Miami and I'm a mathematics major.
Me:
At Universal Studios:
My Pontiac Firebird. I love my car ![]()

Note: I asked MathIsFun permission to post this.
mathsy,
what is the method to find such solutions?
TI-89 says the two solutions are:
x = 2
x = -ln(250)/ln(10)
Well, I'd love to take a look but I havent taken any analysis class so im lost as to where to start. Hopefully that changes next semester when I will take Advanced Calculus.
Also, the proof of continuity deals with analysis, the exercise of finding the K is from Calc1. How come?
OFF-TOPIC:
Ricky, I always wondered what Real Analysis was, is that the same as Advanced Calculus?
I have the number pad memorized from regular computer use and I let my index finger govern numbers 1-4-7, my middle finger 2-5-8 and then the other finger 3-6-9.
This is a very nice game but I get really frustrared when I try to do it really fast (i want to break 90.0) and I mess up by touching another key...I get really mad lol. I turn off the screen and storm out the room hehe ![]()
Well, it is true that back in Calc1 we were told that the sum and product of continuous function are continuous. But one thing is to take it for granted and another thing is to actually prove it which was what Wizard asked. Right?
86.67 now
![]()
In what class are you mentioning?
Make a Venn Diagram for (A - B) - C and then make another Venn Diagram for (A - C) - (B - C) and confirm they are the same.
Do the same for a membership table.
What is the problem?
I wouldnt know how to prove the first one is continuous. I always took for granted all polynomials are continuous. Maybe to prove it you need to use epsilon-delta proofs?
For the second one, the question states to find K such that the piece-wise function f is continuous at x=2. For f to be continuous the sided limits need to be the same and they need to be equal to f(2). So we need the limit as x approaches 2 from the left to be equal to the limit as x approaches 2 from the right.
So we take the limit from the left and we get 4k and we take the limit from the right and we get 4 + k. For the function to be continuous then those two need to be equal. So:
4k = 4 + k
3k = 4
k = 4/3
So now that we know k=4/3 then the limit from the left equals 16/3, from the right equals 16/3 and f(2) = 16/3. So we found our k such that f is continuous.
I cant either.
Isnt the commutative law a set identity itself?
To find relative extrema and saddle points you need to find the partial derivatives Fx and Fy. Set Fx and Fy equal to zero and find the values of x and y that make the partial derivatives equal to zero, which will give you the critical points of the surface.
Now that you have your critical points you can apply this test:
If D > 0 and Fxx > 0 then f has a min at the critical point.
If D > 0 and Fxx < 0 then f has a max at the critical point.
If D < 0 then it is a saddle point.
If D = 0 then you cannot make any conclusions.
Find the gradient of the surface and this vector will be normal to the surface. Having this normal vector you can find the tangent plane and also find the normal line.
Another way is to note that the vector:
Will be normal to the surface. So repeat above steps.
Gradient is defined as a vector with the components being the partial derivatives.
Directional Derivative is defined as the dot product of the gradient and a unit vector.
This is the gradient of F at (1,2). (thanks Daniel123 for providing the code
)
So now you have the gradient. To find the directional derivative, find the vectors from the two points given. Normalize it and then the directional derivative will be the dot product of the gradient and this unit vector.
I like the adding game ![]()
I put up a nice highscore for you all to beat ![]()